速度限制为滚动视图 [英] Speed limit for scroll view
问题描述
我的应用程序的滚动是超级快！ 如何限制滚动视图的滚动速度在我的Android应用程序？ 涡旋可以非常快，它的意义在于，速度滚动。
My app scrolling is super fast! How can I limit the scroll speed of a scroll view in my android app? The scroll can be very fast and it's meaningless to scroll in that speed.
推荐答案
这线程是老了，但我会解决部分问题回复：限制一扔速度。随意发表评论，所以我可以提高我的解决方案。
This thread is old, but I will reply with a partial solution: limiting the fling velocity. Feel free to comment so I can improve my solution.
由于在开发人员培训手册的说明：
As explained in the Developer Training guide:
急张的是，当用户拖动并迅速抬起她的手指发生滚动的类型。
Flinging is the type of scrolling that occurs when a user drags and lifts her finger quickly.
这就是我需要的速度极限。因此，在自定义滚动型（不论水平或垂直） 覆盖一扔这样的方法。
That's where I needed a velocity limit. So, in the Custom ScrollView (whether horizontal or vertical) override fling method like this.
@Override
public void fling(int velocityY) {
int topVelocityY = (int) ((Math.min(Math.abs(velocityY), MAX_SCROLL_SPEED) ) * Math.signum(velocityY));
super.fling(topVelocityY);
}
我发现，velocityY（水平滚动视图，这将是velocityX）可能是之间-16000和16000消极只是意味着滚动回来。我仍然在测试这个值，我也只有一台设备进行了测试。不知道这是否是在旧设备/ API版本相同。我以后还会再来编辑此。
I found that velocityY (in horizontal scrollview, it would be velocityX) could be between -16000 and 16000. Negative just means scrolling back. I'm still testing this values, and I have tested it in only one device. Not sure if it's the same in older devices/API versions. I will come back later to edit this.
(int) ((Math.min(Math.abs(velocityY), MAX_SCROLL_SPEED) ) * Math.signum(velocityY));
我在做什么有获得我不断MAX_SCROLL_SPEED和原velocityY两者中的最小值，然后获得原velocityY的迹象。我们需要标志向后滚动。
What I'm doing there is obtaining the minimum value between my constant MAX_SCROLL_SPEED and original velocityY, then obtaining the sign of the original velocityY. We need the sign to scroll back.
最后，发回修改后的velocityY。
Finally, sending back the modified velocityY.
这是一个部分的解决方案，因为如果用户保持pressing滚动视图，速度不会改变。
It's a partial solution, because if the user keeps pressing the scrollview, the speed won't change.
再次随意提高我的回答，我仍然在学习。
Again, feel free to improve my answer, I'm still learning.
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