newby可以使用一点帮助 [英] newby could use a little help

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问题描述

我想知道是否有人可以了解我需要做些什么呢

代码我已经尝试过所有我知道的内容并且空白。


**错误**场景=场景1,图层=第6层,帧= 115:第1行:'')''或'',''

预期


getURL(http://www.somestore.com/index.php"" _self");


总ActionScript错误:1报告的错误:1

解决方案

Leslie Cox在2007年11月22日下午12:22说了以下内容:


嗨我想知道是否有人可以了解我需要做什么用这个

代码我已经尝试过我所知道的所有内容并且空白。


**错误**场景=场景1,图层=第6层,帧= 115:第1行:'')''或'',''

预期

getURL(http://www.somestore.com/index.php"" _self");


总ActionScript错误:1报告的错误:1



嗯。也许你应该尝试一个面向Flash的组,因为ActionScript是

Flash。


-

Randy

机会有利于准备好的心灵

comp.lang.javascript常见问题 - http://jibbering.com/faq/index.html

Javascript最佳实践 - http://www.JavascriptToolbox.com/bestpractices/


Leslie Cox写道:
< blockquote class =post_quotes>
**错误**场景=场景1,图层=第6层,帧= 115:第1行:'')''或'',''

预期


getURL(http://www.somestore.com/index.php"" _self");



^


总ActionScript错误:1报告的错误:1



由于ActionScript是一个ECMAScript实现,因此上面的

在语法上是不正确的。如果是_self是getURL()的第二个参数

,你必须用逗号分隔它:


getURL(http://www.somestore .com / index.php"," _self");

PointedEars

-

Prototype.js是由不喜欢的人写的不知道javascript for people

谁不懂javascript。不知道javascript的人不是设计使用javascript的系统的最佳建议来源。

- Richard Cornford,cljs,< f8 ** *****************@news.demon.co.uk>


Thomas''PointedEars''Lahn写道:


Leslie Cox写道:


> **错误**场景=场景1,图层=第6层,框架= 115:第1行:'')''或'',''
预期

getURL(http://www.somestore.com/index.php" " _self");



^


>总ActionScript错误:1报告的错误:1



由于ActionScript是一个ECMAScript实现,以上是

语法不正确。如果是_self是getURL()的第二个参数

,你必须用逗号分隔它:


getURL(http://www.somestore .com / index.php"," _self");



并且不要忘记附上的报价:


getURL(" http://www.somestore。 com / index.php"," _self");

PointedEars

-

"使用任何版本的Microsoft Frontpage创建你的网站。 (这不会是b $ b阻止人们查看你的来源,但是没有人会想要窃取它。)"

- 来自< http:// www.vortex-webdesign.com/help/hidesource.htm>


Hi I wonder if anyone could shed some light on what I need to do with this
code I have tried everything I know and come up blank.

**Error** Scene=Scene 1, layer=Layer 6, frame=115:Line 1: '')'' or '',''
expected

getURL(http://www.somestore.com/index.php" "_self");

Total ActionScript Errors: 1 Reported Errors: 1

解决方案

Leslie Cox said the following on 11/22/2007 12:22 PM:

Hi I wonder if anyone could shed some light on what I need to do with this
code I have tried everything I know and come up blank.

**Error** Scene=Scene 1, layer=Layer 6, frame=115:Line 1: '')'' or '',''
expected

getURL(http://www.somestore.com/index.php" "_self");

Total ActionScript Errors: 1 Reported Errors: 1

Hmmm. Maybe you should try a Flash oriented group since ActionScript is
Flash.

--
Randy
Chance Favors The Prepared Mind
comp.lang.javascript FAQ - http://jibbering.com/faq/index.html
Javascript Best Practices - http://www.JavascriptToolbox.com/bestpractices/


Leslie Cox wrote:

**Error** Scene=Scene 1, layer=Layer 6, frame=115:Line 1: '')'' or '',''
expected

getURL(http://www.somestore.com/index.php" "_self");

^

Total ActionScript Errors: 1 Reported Errors: 1

Since ActionScript is an ECMAScript implementation, the above is
syntactically incorrect. If "_self" is to be the second argument
to getURL(), you will have to delimit it with a comma:

getURL(http://www.somestore.com/index.php", "_self");
PointedEars
--
Prototype.js was written by people who don''t know javascript for people
who don''t know javascript. People who don''t know javascript are not
the best source of advice on designing systems that use javascript.
-- Richard Cornford, cljs, <f8*******************@news.demon.co.uk>


Thomas ''PointedEars'' Lahn wrote:

Leslie Cox wrote:

>**Error** Scene=Scene 1, layer=Layer 6, frame=115:Line 1: '')'' or '',''
expected

getURL(http://www.somestore.com/index.php" "_self");

^

>Total ActionScript Errors: 1 Reported Errors: 1


Since ActionScript is an ECMAScript implementation, the above is
syntactically incorrect. If "_self" is to be the second argument
to getURL(), you will have to delimit it with a comma:

getURL(http://www.somestore.com/index.php", "_self");

And don''t forget the enclosing quotes:

getURL("http://www.somestore.com/index.php", "_self");
PointedEars
--
"Use any version of Microsoft Frontpage to create your site. (This won''t
prevent people from viewing your source, but no one will want to steal it.)"
-- from <http://www.vortex-webdesign.com/help/hidesource.htm>


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