如何将十六进制值的二进制数组转换为十进制字符串 [英] how to convert a binary array with hex values into decimal string

问题描述

我有一个包含十六进制值的字节数组。我想将其6个字节转换为十进制值，并将结果显示为字符串。


我什么时候必须考虑结束？


i试图基本上直接分配到unsigned long我看到了它确实正确地转换它但我没有使用任何endianess。虽然我仍然没有把它转换为字符串。


我什么时候使用endianess（我在unbuntu上开发但我知道我必须将它移植到sun box / hp box也许）。我确实读过某个地方，只要无符号长尺寸<= 2它就可以在任何方框上工作。这是真的？如果是这样的原因？


您的帮助将不胜感激。

i have a byte array that contains hex values. i want to convert 6 bytes of it into decimal values and display the result as a string.

also when do i have to take the endianess into consideration?

i have tried to basically do a direct assignment to unsigned long and i saw that it did convert it correctly but i did not use any endianess. although i still did not convert it into a string.

when do i use endianess ( i am developing on unbuntu but i know i will have to port this to a sun box/hp box maybe). i did read somewhere that as long as the unsigned long size is <= 2 it should work on any box. is this true? if so why?

your help would be greatly appreciated.

推荐答案

BTW我不使用.net c ++所以我不能使用bitconverter等。

BTW i am not using .net c++ so i cannot use bitconverter etc.

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我认为你不必担心除非您执行以下操作之一，否则将使用字节顺序：

• 您的程序有时会通过一种类型访问相同的数据项，有时也会通过另一种不同大小的类型访问相同的数据项。例如，您有一个32位数据项有时作为无符号长整数访问，有时作为无符号字符数组访问。
• 您试图访问一个必须也可以访问的数据项系统;也就是说，系统不能保证是相同的处理器和编译器组合。例如，您的PC正在写入可能由Linux PC读取的二进制文件。
• 您正在访问内存映射的I / O设备。

I don''t think you need to worry about endianness unless you''re doing one of the following:

• Your program accesses the same data item sometimes via one type and sometimes via another, differently sized, type. For example, you have a 32-bit data item that is sometimes accessed as an unsigned long and sometimes as an array of unsigned chars.
• You seek to access a data item that must also be accessible to a dissimilar system; that is, a system that is not guaranteed to be the same processor and compiler combination. For example, your PC is writing to a binary file that might be read by a Linux PC.
• You are accessing memory-mapped I/O devices.

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