在运行时会发生什么？ [英] What happens exactly during run time?
问题描述
班级{
public：
int x;
just（）{x = 1234; }
just（int i）{x = i;}
~just（）{cout<< "我们在这里 ;}
};
int main（）
{
只是j1;
只是* jptr = new just（5432）;
delete（jptr）;
delete（& j1）;
cout<< Test Out \\\
;
返回0;
}
执行析构函数后，为J1程序调用Visual中止中止br />
Studio 6
class just{
public :
int x;
just(){ x=1234; }
just(int i){ x = i;}
~just(){ cout << " Here We Are\n" ;}
};
int main()
{
just j1;
just *jptr =new just(5432);
delete( jptr);
delete( &j1);
cout << "Test Out \n" ;
return 0;
}
After executing destructor for J1 program calls for an abort in Visual
Studio 6
推荐答案
Pranav写道：
Pranav wrote:
class只需{
public：
int x;
just（）{x = 1234; }
just（int i）{x = i;}
~just（）{cout<< "我们在这里 ;}
};
int main（）
{
只是j1;
只是* jptr = new just（5432）;
delete（jptr）;
delete（& j1）;
cout<< Test Out \\\
;
返回0;
}
执行析构函数后，为J1程序调用Visual中止中止br />
Studio 6
class just{
public :
int x;
just(){ x=1234; }
just(int i){ x = i;}
~just(){ cout << " Here We Are\n" ;}
};
int main()
{
just j1;
just *jptr =new just(5432);
delete( jptr);
delete( &j1);
cout << "Test Out \n" ;
return 0;
}
After executing destructor for J1 program calls for an abort in Visual
Studio 6
那么你期待什么？ j1没有动态分配。
-
Ian Collins。
Well what did you expect? j1 wasn''t dynamically allocated.
--
Ian Collins.
Pranav ha scritto：
Pranav ha scritto:
delete（& j1）;
delete( &j1);
以前的新品在哪里？
Where is its previous new?
Ya我知道那件事，但当我打电话''删除（& j1）''之后调用
''j1''的析构函数后，会出现一个窗口显示''Abort / Ignore /
重试''。为什么会出现这种情况？任何人都可以解释运行期间发生了什么吗？
Ya I know that thing, But When I call ''delete(&j1)'' the destructor for
''j1'' is called after this there is window appears saying ''Abort/Ignore/
Retry''. Why exactly this behaviour occurs? Can any one explain what
happens during runtime?
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