Char *操作 [英] Char* operation
问题描述
对不起，
无法想出一个更好的头衔，但这就是我要做的事情：
我正在制作一个小型控制台应用程序来读取.pak文件（它们来自游戏）。我正在逐步构建它，所以我不会犯错误。
现在我正在尝试获取存储在这样的.pak文件中的文件数量。这通常是通过从.pak文件读取前2个字节，将它们反转然后将它们解释为标题来完成的。
我能够通过使用fstream对象读取前2个字节（ifstream）并将2个字节读入char *缓冲区。
现在我有问题，如何反转2个字节，然后将其解释为整数/短。 ？
我尝试在char *中切换地方的字节（作为数组处理），但没有给我我想要的结果。
示例：
24 00应读为00 24，结果为36整数。
Sorry,
couldn''t come up with a better title, but here''s what I''m trying to do:
I''m making a small console application that reads .pak files (they''re from a game). I''m building it in steps, so I don''t make errors.
Right now i''m trying to obtain the amount of files stored inside such a .pak file. This is normally done by reading the first 2 bytes from the .pak files, reversing them and then interpreting them as a header.
I''m able to read the first 2 bytes by using an fstream object (ifstream) and read 2 bytes into a char* buffer.
Now I have as question, how can I reverse the 2 bytes, and then interpret it as an integer/short. ?
I tried switching the bytes of place inside the char* (treated as array) but didn''t give me the result I wanted.
example :
24 00 should be read as 00 24, and resulting in 36 as integer.
推荐答案
这两个字节在你的文件中存储了big endian，你希望它们在
endian命令中。在short int中读取这两个字节并将ntohs（）宏
应用于此：
The two bytes are stored big endian in your file and you want them to be in little
endian order. Read those two bytes in a short int and apply the ntohs() macro
to it like this:
好的，我设法得到了更多。
这里是我正在使用的代码，它是非常粗糙的只是得到此刻只有2个字节：
Ok, I managed to get a bit further.
Here''s the code I''m currently using, it''s very rough just to get the 2 bytes at the moment, nothing else:
没关系找到它:)
必须链接到ws2_32.lib
但现在我得到的输出：金额Map.pak中的文件：9216
但它应该是：Map.pak中的文件数量：36。
是转换进行错了呢？
never mind found it :)
had to link to ws2_32.lib
but now I get as output : Amount of files in Map.pak : 9216
but it should be : Amount of files in Map.pak : 36.
is the conversion going wrong then?
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