乳宁在Android标准的Java code [英] Runing a standard Java code on Android

问题描述

我要运行在Android上我的Java code。但我不熟悉Activites。我怎么能叫WordPuzzle上的活动？

Android的活动：

 公共类益智延伸活动{

    公共无效的onCreate（包savedInstanceState）{
        super.onCreate（savedInstanceState）;
        的setContentView（R.layout.main）;
    }
 

Java的code：

 公共类WordPuzzle {.....

  公共设置＆LT;字符串＆GT; findWords（的char [] []谜题，设置＆LT;字符串＆GT;的话）{.....

  私人诠释findMinimumWordLength（集＆LT;字符串＆GT;的话）{.....

  私人设置＆LT;字符串＆GT; findPossibleWords（的char [] []拼图，诠释minimumWordLength）{.....

  公共无效的主要（字串的args []）{
            WordPuzzle程序=新WordPuzzle（）;
            的char [] []拼图= {
                                {F，Y，Y，H，N，R，D}，
                                {R，L，J，C，I，N，U}，
                                {'A'，'A'，'W'，'A'，'A'，'H'，'R'}，
                                {'N'，'T'，'K'，'L'，'P'，'N'，'E'}，
                                {C，I，L，F，S，A，P}，
                                {'E'，'O'，'G'，'O'，'T'，'P'，'N'}，
                                {'H'，'P'，'O'，'L'，'A'，'N'，'D'}
                              };
            设置＆LT;字符串＆GT;字=新的HashSet＆LT;字符串＆GT;（）;
            words.add（FRANCE）;
            words.add（波兰）;
            words.add（JAPAN）;
            words.add（荷兰）;
            设置＆LT;字符串＆GT; wordsFound = program.findWords（拼图，字）;
            对（串词：wordsFound）{
                的System.out.println（字）;
            }
        }
    }
}
 

解决方案

 公共类益智延伸活动{

     公共无效的onCreate（包savedInstanceState）{
            super.onCreate（savedInstanceState）;
            的setContentView（R.layout.main）;
            WordPuzzle WP =新WordPuzzle（）; //你需要做的main（）静态函数来避免这个
            字符串的args [] = {};
            wp.​​main（参数）;
  }
 

但我不认为的System.out.println（）将工作，至少不会在这里用户可以查看它。 更改layout.main到的TextView ，并把你的输出有可能

I want to run my Java code on Android. But I'm not familiar with Activites. How can I call WordPuzzle on an Activity?

Android activity:

public class Puzzle extends Activity {

    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
    }

Java code:

public class WordPuzzle {.....

  public Set<String> findWords(char[][] puzzle, Set<String> words) {.....

  private int findMinimumWordLength(Set<String> words) {.....

  private Set<String> findPossibleWords(char[][] puzzle, int minimumWordLength) {.....

  public void main(String args[]) {
            WordPuzzle program = new WordPuzzle();
            char[][] puzzle = { 
                                {'F','Y','Y','H','N','R','D'},
                                {'R','L','J','C','I','N','U'},
                                {'A','A','W','A','A','H','R'},
                                {'N','T','K','L','P','N','E'},
                                {'C','I','L','F','S','A','P'},
                                {'E','O','G','O','T','P','N'},
                                {'H','P','O','L','A','N','D'}
                              };
            Set<String> words = new HashSet<String>();
            words.add("FRANCE");
            words.add("POLAND");
            words.add("JAPAN");
            words.add("HOLLAND");
            Set<String> wordsFound = program.findWords(puzzle, words);
            for(String word : wordsFound) {
                System.out.println(word);
            }
        }
    }
}

解决方案

  public class Puzzle extends Activity {

     public void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.main);
            WordPuzzle wp = new WordPuzzle(); // you need to make main() a static function to avoid this
            String args[] = {""};
            wp.main(args);
  }

but i dont think System.out.println() will work, at least not where the user could view it. Change layout.main to a TextView and put your output there maybe

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