这个指针 [英] this pointer

问题描述

有关此的一些问题指针：


1.要进行赋值功能，


Stribg& String :: operator =（const String& other）

{

...

返回* this;

}


我很难理解为什么* this匹配String&这里。可以

有人对此有所了解吗？


2.在静态成员函数中没有这个指针可以在里面访问

呢？


3.在const成员函数中是this。 const类型的指针

非const成员中的非const类型？


提前感谢！

解决方案

>关于这个的一些问题指针：

1.制作赋值函数，

Stribg& String :: operator =（const String& other）
{
...
返回* this;
}


返回类型是String& （字符串引用）和赋值

运算符正在传递对自身的引用。分配完成。
我很难理解为什么* this匹配String&这里。
有人可以对此有所了解吗？

2.在静态成员函数中没有这个指针可以访问
里面吗？


静态成员函数中没有这个指针。
3.在const成员函数中是this。 const类型的指针，而非const成员中的非const类型？

是的，这个指针是const成员函数中的const指针。

提前致谢！

" stub" < ST ** @ asof.com>在消息新闻中写道：1qzob.22753

E ********** @ bgtnsc05-news.ops.worldnet.att.net ... < blockquote class =post_quotes>关于this的一些问题指针：

1.要进行赋值功能，

Stribg& String :: operator =（const String& other）

...
返回*这个;
}

我很难理解为什么* this匹配
String&这里。有人可以对此有所了解吗？


您在赋值运算符中返回* this，以便

可以执行以下操作：


A = b = C; // a，b，c是String'和

// b返回（* this）以便a可以分配

2.在静态成员函数中不是这个指针
可以进入吗？

静态方法没有这个指针，因为它们

与特定的对象实例无关。


HTH，

- J.

Some questions about "this" pointer:

1. To make an assignment function,

Stribg &String::operator=(const String &other)
{
...
return *this;
}

I have hard time to understand why "*this" matches a "String &" here. Could
someone shed some light on this?

2. In a static member function aren''t there "this" pointer accessible inside
it?

3. In a const member function is the "this" pointer of const type while
non-const type in a non-const member?

Thanks in advance!

解决方案

> Some questions about "this" pointer:

1. To make an assignment function,

Stribg &String::operator=(const String &other)
{
...
return *this;
}
The return type is a String & (String reference) and the assignment
operator is passing back a reference to itself one the assignment is done.
I have hard time to understand why "*this" matches a "String &" here. Could someone shed some light on this?

2. In a static member function aren''t there "this" pointer accessible inside it?
No there is no this pointer in a static member function.
3. In a const member function is the "this" pointer of const type while
non-const type in a non-const member?
Yes the this pointer is a const pointer in a const member function.
Thanks in advance!

"stub" <st**@asof.com> wrote in message news:1qzob.22753

E**********@bgtnsc05-news.ops.worldnet.att.net...

Some questions about "this" pointer:

1. To make an assignment function,

Stribg &String::operator=(const String &other)
{
...
return *this;
}

I have hard time to understand why "*this" matches a
"String &" here. Could someone shed some light on this?
You return *this in an assignment operator so that
it''s possible to do things like:

a=b=c; // a,b,c are String''s and
// b returns (*this) so that a can be assigned
2. In a static member function aren''t there "this" pointer
accessible inside it?

Static methods have no "this" pointer, because they
are not associated with a particular instance of an object.

HTH,
- J.

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