基于子表记录选择打开图像 [英] Open Image Based on Subform Record Selected

问题描述

我有一个可访问的可搜索表单，在子表单中显示结果。

子表单结果中的一个字段是ImagePath。


我希望能够从结果中选择一条记录，然后单击一个按钮，使用ImagePath打开该特定记录的pdf。

I have a access searchable form that displays results in a subform.

One of the fields in the subform results is ImagePath.

I want to be able to select a record from the results, then click a button that would open a pdf for that specific record using ImagePath.

推荐答案

您可以使用记录上的按钮，代码如下：

You could use a button on the record with code like the following:

展开 | 选择 | Wrap | 行号

这是一个子表单的事实并没有改变任何东西。任何形式都可以使用相同的方法。


您也可以在更改记录时触发代码，或者双击控件及其中的图像路径。这两个都会为按钮节省额外的空间，如果表单处于连续表单模式，这尤其是一个问题。

The fact that this is a subform doesn''t change anything. The same approach could be used on any form.

You could also trigger the code on either the change of record, or double-clicking on the control with the image path in it. Both of these would save the extra space for the button, which is especially a problem if the form is in Continuous Form mode.

Curios你将如何实现这一点：

Curios how would you accomplish this:

您还可以触发记录更改的代码

You could also trigger the code on either the change of record

我想象使用子表格当前事件，但这会触发在很多不需要的情况下，你必须编写代码。


如果图像路径是一个可见的控件，另一个选项（根据NeoPa的建议）可能是更改控件属性以将其格式化为超链接，然后编码开头例如，在DoubleClick上发生。

I imagine using the subforms current event, but that would fire in alot of unwanted cases, which you would have to code for.

If the imagepath is a visible control, another option (as per NeoPa''s suggestion) could be to change the controls properties to format it as a hyperlink, and then code the opening to occur on DoubleClick for example.

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