关系运算符 [英] Relational Operators

问题描述

在我的绝对新手的C指南中，Greg Perry

在哪里说明关系运算符如何工作它给出了

以下示例：


int i = 5;


因此以下陈述为真：


int i == 1


嗯，对我说整数我是5，而5等于1.


有人能帮我理解吗？

谢谢

解决方案

Al *********** @ gmail.com 写道：

在我的绝对初学者Greg Perry的C指南

指示关系运算符如何工作它给出了

以下示例：


int i = 5;


所以以下陈述是正确的：


int i == 1

==不是关系运算符（它是一个相等运算符）和

后者不是声明，也不是有效声明。

你确定你输入的内容与

完全相同这本书？

-

C有它的问题，但从头开始设计的语言也有一些，

我们知道C'的问题。

--Barne Stroustrup

3月4日下午4:55，Ben Pfaff< b。 .. @ cs.stanford.eduwrote：

AliceB.Tok ... @ gmail.com写道：

在我的Absolute Beginner's C指南中由Greg Perry撰写

在哪里说明关系运算符如何工作它给出了

以下示例：

int i = 5;

所以以下陈述为真：

int i = = 1

==不是关系运算符（它是一个相等运算符）和

后者不是声明，也不是它是一个有效的声明。

你确定你输入的内容与

中出现的完全相同吗？

-

C有它的问题，但是从头开始设计的语言也有一些，

我们知道C'的问题。

--Barne Stroustrup

我的书在关系运算符下列出==，我使用的是

单词陈述也直接来自书中。虽然，我很有意识到我没有理解我的语言。无论如何，我的帖子中有一个

的错误，但我认为它不会改变它不是什么事实

有效声明

int i = 5


以下是真实的：


i == 1

Al *********** @ gmail.com 写道：

[我的书指出，给定]

int i = 5


以下是真的：


i == 1

不，这不是真的。也就是说，如果我的值为

，则i == 1为假5.如果你的书真的说明了，那就错了。

-

如果它没有给静态这个词带来新的含义，那么它就不是一个新的C标准。

- C99上的Peter Seebach

In my Absolute Beginner''s Guide to C book by Greg Perry
where it is instruction how relational operators work it gives the
following example:

int i = 5;

so the following statement is true:

int i == 1

Um, to me that says integer i is 5, and 5 is equal to 1.

Can someone help me understand this?
Thanks

解决方案

Al***********@gmail.com writes:

In my Absolute Beginner''s Guide to C book by Greg Perry
where it is instruction how relational operators work it gives the
following example:

int i = 5;

so the following statement is true:

int i == 1

== is not a relational operator (it is an equality operator) and
the latter is not a statement, nor is it a valid declaration.
Are you sure that you''ve typed that in exactly as it appears in
the book?
--
"C has its problems, but a language designed from scratch would have some too,
and we know C''s problems."
--Bjarne Stroustrup

On Mar 4, 4:55 pm, Ben Pfaff <[e-mail]:

[e-mail] writes:

In my Absolute Beginner''s Guide to C book by Greg Perry
where it is instruction how relational operators work it gives the
following example:

int i = 5;

so the following statement is true:

int i == 1

== is not a relational operator (it is an equality operator) and
the latter is not a statement, nor is it a valid declaration.
Are you sure that you''ve typed that in exactly as it appears in
the book?
--
"C has its problems, but a language designed from scratch would have some too,
and we know C''s problems."
--Bjarne Stroustrup

Well my book lists == under relational operators, and my use of the
word statement was also directly from the book. Though, I''m quite
aware that I haven''t got the lingo down. Anyway, there was one
mistake in my post, but I don''t think it changes the fact it isn''t a
valid declaration
int i = 5

the follow is true:

i == 1

Al***********@gmail.com writes:

[My book states that, given]
int i = 5

the follow is true:

i == 1

Nope, it''s not true. That is, i == 1 is false if i has the value
5. If your book really states that, it''s just wrong.
--
"It wouldn''t be a new C standard if it didn''t give a
new meaning to the word `static''."
--Peter Seebach on C99

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