将指针存储在向量中？ [英] Store pointers in a vector?
问题描述
我有一个类Conception，我在向量中有这个，它应该是：
vector< Conception> VEK; // vector
vector< Conception> :: iterator vek; // vet的迭代器
但是如果我想要指向类Conception的指针呢？怎么
我可以这样做吗？我应该如何编写声明这个
向量的迭代器？
I have a class Conception and I have this in a vector, it should be:
vector<Conception> vek; // vector
vector<Conception>::iterator vek; // iterator to vek
But what if I want to have pointers to class Conception instead? How
can I do that? And how should I write to declare an iterator to this
vector?
推荐答案
" Roland Bengtsson" < RO **************** @ home.se>在消息中写道
news：49 ************************** @ posting.google.c om ...
"Roland Bengtsson" <ro****************@home.se> wrote in message
news:49**************************@posting.google.c om...
我有一个类Conception，我在矢量中有这个，它应该是：
vector< Conception> VEK; // vector
vector< Conception> :: iterator vek; // vet的迭代器
但是，如果我想要指向类Conception的指针呢？我怎么能这样做？我应该如何编写声明这个
向量的迭代器？
I have a class Conception and I have this in a vector, it should be:
vector<Conception> vek; // vector
vector<Conception>::iterator vek; // iterator to vek
But what if I want to have pointers to class Conception instead? How
can I do that? And how should I write to declare an iterator to this
vector?
我只是转向C ++，所以这可能是错的，但不是'' ta指针只是一个
数据类型和其他什么一样？我认为你可以这样声明：
vector< Conception *> VEK; //矢量
否？
Jeremy
I am just moving to C++, so this may be wrong, but isn''t a pointer just a
data type like anything else? I would think you could declare it like this:
vector<Conception*> vek; // vector
No?
Jeremy
" ; Roland Bengtsson < RO **************** @ home.se>在消息中写道
news：49 ************************** @ posting.google.c om ...
"Roland Bengtsson" <ro****************@home.se> wrote in message
news:49**************************@posting.google.c om...
我有一个类Conception，我在矢量中有这个，它应该是：
vector< Conception> VEK; // vector
vector< Conception> :: iterator vek; // vet的迭代器
两个不同的对象有相同的名字（''vek''）！
但是如果我想有指针怎么办？改为Conception而不是？
没问题。
我怎么能这样做？
指定任何其他类型元素的方式相同。
vector< Conception *> vek;
我该如何编写声明这个
向量的迭代器？
I have a class Conception and I have this in a vector, it should be:
vector<Conception> vek; // vector
vector<Conception>::iterator vek; // iterator to vek
You have the same name (''vek'') for two different objects!
But what if I want to have pointers to class Conception instead?
No problem.
How
can I do that?
Same way you specify any other type element.
vector<Conception *> vek;
And how should I write to declare an iterator to this
vector?
vector< Conception *>： ：iterator vi;
当然，现在你负责管理你的指针所指出的任何内存
。
-Mike
vector<Conception *>::iterator vi;
Of course now you''re responsible for managing any memory pointed
to by your pointers.
-Mike
Jeffrey Schwab写道：
Jeffrey Schwab wrote:
Jeremy Cowles写道：
Jeremy Cowles wrote:
" ; Roland Bengtsson < RO **************** @ home.se>在消息中写道
新闻：49 ************************** @ posting.google.c om ...
"Roland Bengtsson" <ro****************@home.se> wrote in message
news:49**************************@posting.google.c om...
我有一个类Conception，我在矢量中有这个，它应该是：
vector< Conception> VEK; // vector
vector< Conception> :: iterator vek; // vet的迭代器
但是，如果我想要指向类Conception的指针呢？我怎么能这样做？我应该如何编写声明这个
向量的迭代器？
我只是转向C ++，所以这可能是错的，但不是指针只是一个
数据类型和其他什么类似？我认为你可以宣布它像
这样：
vector< Conception *> VEK; //矢量
没有？
Jeremy
I have a class Conception and I have this in a vector, it should be:
vector<Conception> vek; // vector
vector<Conception>::iterator vek; // iterator to vek
But what if I want to have pointers to class Conception instead? How
can I do that? And how should I write to declare an iterator to this
vector?
I am just moving to C++, so this may be wrong, but isn''t a pointer just a
data type like anything else? I would think you could declare it like
this:
vector<Conception*> vek; // vector
No?
Jeremy
是的，但要确保你已经宣布了向量，并且你'正在寻找正确的命名空间：
#include< vector>
int main（）
{
std ::矢量<概念* GT; VEK; //无用的评论
Right, but make sure you''ve declared vector, and that you''re looking in
the right namespace for it:
#include <vector>
int main( )
{
std::vector<Conception*> vek; // useless comment
哎呀！这应该是：
class Conception;
std :: vector< Conception *> VEK; //无用的评论
}
Whoops! That should be:
class Conception;
std::vector<Conception*> vek; // useless comment
}
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