循环问题 [英] loop question
问题描述
Hi Group，
我可以问以下问题吗？
for（i = 0;（c = getchar（））！= EOF& & c！=''\ n''; ++ i）
line [i] = c;
我发现当c == ''\ n''是真的，循环是
终止，但我仍然增加。我的印象是
终止循环不应该增加i。
谢谢。
morpheus写道：嗨组，
我可以问以下问题吗？
（i = 0;（c = getchar（））！= EOF&& c！=''\ n''; ++ i）
line [i] = c;
我发现当c ==''\ n''为真时，循环终止，但我仍然增加。我的印象是
终止循环不应该增加i。
谢谢
你可以发一个示例输入输出该计划以及
您的预期输出
ranjmis ha scritto：morpheus写道：嗨组，
请问以下问题？
for（i = 0;（c = getchar（））！= EOF&& c！=''\ n''; ++ i）
line [i] = c;
我发现当c ==''\ n''为真时，循环终止，但我仍然是递增。我的印象是
终止循环不应该增加i。
谢谢
请你发一个程序的示例输入输出与
你的预期输出
而且，我想补充一下，请你发一个完整的代码*，而不仅仅是一个
片段。所以我们可以看到你的循环出了什么问题。
David
-
Linux注册用户＃334216
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员工>> http://www.debianizzati.org <<
ranjmis写道：
for（i = 0;（c = getchar（ ））！= EOF&& c！=''\ n''; ++ i）
line [i] = c;
请你发一个样本输入 - 计划的输出以及
您的预期输出
我的实际代码是：
for（i = 0;（c = getchar（））！= EOF&& c！=''\ n''; ++ i）
line [i] = c;
if（c ==''\ n''|| c == EOF）
{
++ i;
line [i] = ''\ n'';
++ i;
line [i] =''\ 0'';
}
测试输入; test
请注意，测试后面是4个空格和换行符号。
我期待线路包含''test\\\
\'''，但它包含
test''something''\ n0。现在，我确实感谢第5行中的++ i引起了这种行为，但我不完全理解为什么第5行不会是必要的，因为我认为不需要
。
Hi Group,
May I ask the following?
for (i=0; (c=getchar()) != EOF && c != ''\n''; ++i)
line[i]=c;
What I am finding is that when c == ''\n'' is true, the loop is
terminated but i is still incremented. I was under the impression that
termination of the loop should not increment i.
Thank you.
morpheus wrote:Hi Group,
May I ask the following?
for (i=0; (c=getchar()) != EOF && c != ''\n''; ++i)
line[i]=c;
What I am finding is that when c == ''\n'' is true, the loop is
terminated but i is still incremented. I was under the impression that
termination of the loop should not increment i.
Thank you
can you please post a sample input-output of the program along with
your "expected" output
ranjmis ha scritto:morpheus wrote:Hi Group,
May I ask the following?
for (i=0; (c=getchar()) != EOF && c != ''\n''; ++i)
line[i]=c;
What I am finding is that when c == ''\n'' is true, the loop is
terminated but i is still incremented. I was under the impression that
termination of the loop should not increment i.
Thank you
can you please post a sample input-output of the program along with
your "expected" output
And, I''d add, could you please post a *complete code*, not just a
snippet. So we can see what''s wrong with your loop.
David
--
Linux Registered User #334216
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Staff >> http://www.debianizzati.org <<
ranjmis wrote:
for (i=0; (c=getchar()) != EOF && c != ''\n''; ++i)
line[i]=c;
can you please post a sample input-output of the program along with
your "expected" output
My actual code is this:
for (i=0; (c=getchar()) != EOF && c != ''\n''; ++i)
line[i]=c;
if (c == ''\n'' || c == EOF )
{
++i;
line[i]=''\n'';
++i;
line[i]=''\0'';
}
Test input; "test
"
Note that test is followed by 4 blank spaces and a newline token.
I was expecting "line" to contain ''test\n\0'' but it contains
test''something''\n\0. Now, I do appreciate that ++i in line 5 is
causing this behaviour, but I do not fully appreciate why line 5 would
not be necessary, I guess.
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