更多的pythonic圈？ [英] More pythonic circle?
问题描述
我为个人项目编写了以下代码。我需要一个函数
，它将在二维数组中绘制一个实心圆。我找到了
Bresenham的算法，并生成了这段代码。请告诉我有更好的方法来实现这个目标。
导入numpy
def circle（ field = None，radius，center =（0,0），value = 255，）：
''''''返回距离点''半径''内的点列表
''center''。''''''
if field == None：
field = numpy.zeros（（radius，radius） ），''你'）
cx，cy = center
filllist = []
dy，dx = 0，radius
r2 =半径** 2
而dy< =（半径* .71）：#sin为45度
如果dx ** 2 + dy ** 2< = r2：
for x in range（dx）：
filllist.append（（x，dy））
dy + = 1
否则：
dx- = 1
如果dx< dy：break
resultlist = [ ]
for（i，j）填写表：
field [cx + i] [cy + j] = value
field [cx + j] [cy + i] =值
字段[cx-j] [cy + i] =值
字段[cx-i] [cy + j] =值
字段[cx-i] [cy-j] =值
字段[cx-j] [c yi] =价值
字段[cx + j] [cy-i] =值
字段[cx + i] [cy-j] = value
返回字段
I wrote the following code for a personal project. I need a function
that will plot a filled circle in a two dimensional array. I found
Bresenham''s algorithm, and produced this code. Please tell me there''s
a better way to do this.
import numpy
def circle(field=None,radius,center=(0,0),value=255,):
''''''Returns a list of points within ''radius'' distance from point
''center''.''''''
if field==None:
field=numpy.zeros((radius,radius),''u'')
cx,cy=center
filllist=[]
dy,dx=0,radius
r2=radius**2
while dy<=(radius*.71): # sin of 45 degrees
if dx**2+dy**2<=r2:
for x in range(dx):
filllist.append((x,dy))
dy+=1
else:
dx-=1
if dx<dy : break
resultlist=[]
for (i,j) in filllist:
field[cx+i][cy+j]=value
field[cx+j][cy+i]=value
field[cx-j][cy+i]=value
field[cx-i][cy+j]=value
field[cx-i][cy-j]=value
field[cx-j][cy-i]=value
field[cx+j][cy-i]=value
field[cx+i][cy-j]=value
return field
推荐答案
OTTOMH，急于出门：从不介意Pythonic，以下申请
任何语言：
（1）准确度：（a）如果我错了就起诉我，但我认为你需要范围（dx + 1）
使dx像素填入（b）0.71后可能有用的几个数字
可能有用
（2）效率：似乎是范围（dy，dx） +1）可以节省一些磨损和撕掉电路上的
:-)
（3）易读性：这个剧本没有奖品，绝对是
最小号码太空人物:-)
我想我在
档案中有一篇关于更好的Bresenham的文章;以后会把它挖出来。
干杯，
John
OTTOMH, in a rush to go out: never mind Pythonic, following apply to
any language:
(1) accuracy: (a) sue me if I''m wrong, but I think you need range(dx+1)
so that the dx pixel is filled in (b) a few more digits after 0.71
might be useful
(2) efficiency: seems that range(dy, dx+1) would save some wear & tear
on the circuitry :-)
(3) legibility: there''s no prize for the script with the absolutely
minimum number of space characters :-)
I think I''ve got an article on better Bresenham somewhere in the
archives; will dig it out later.
Cheers,
John
John Machin写道：
John Machin wrote:
OTTOMH，急于出去：从不介意Pythonic，以下申请
任何语言：
（1）准确性：（a）起诉我，如果我错了，但我认为你需要范围（dx + 1）
以便dx像素填充
Hmm。我觉得你是对的。谢谢。 （b）在0.71
之后可能有用几个数字
45度的正弦实际上是.707 ...我收尾了，因为我正在使用
< = 。想象一下就可以说清楚了。 （2）效率：似乎范围（dy，dx + 1）可以节省一些磨损和在电路上撕裂:-)
我花了几分钟才弄明白你的意思。这将
肯定有助于减少重复坐标。再次感谢。
（3）易读性：对于具有绝对最小空格字符数的脚本没有奖品:-)
True。我假设你说我应该更好地使用cx，cy，dx和dy
名字。我可能会。到目前为止，我只是在玩这个，而不是真的希望其他人阅读它。
我想我有一篇关于更好的Bresenham的文章在档案馆中;我会在以后挖掘它。
OTTOMH, in a rush to go out: never mind Pythonic, following apply to
any language:
(1) accuracy: (a) sue me if I''m wrong, but I think you need range(dx+1)
so that the dx pixel is filled in Hmm. I think you''re right. Thanks. (b) a few more digits after 0.71
might be useful Sine of 45 degrees is actually .707... I rounded up, since I was using
<=. Figured that would make it clear. (2) efficiency: seems that range(dy, dx+1) would save some wear & tear
on the circuitry :-) It took me a few minutes to figure out waht you meant here. This will
certainly help reduce the repeated coordinates. Thanks, again.
(3) legibility: there''s no prize for the script with the absolutely
minimum number of space characters :-) True. I assume your saying I should make cx,cy,dx, and dy better
names. I probably will. Up to now I was just playing around with
this, and not really expecting anyone else to read it.
I think I''ve got an article on better Bresenham somewhere in the
archives; will dig it out later.
我一定很感激。事实上，我正在努力寻找一个体面的b $ b球体版本，并且谷歌无处可去。我试图用自己的方式来计算
，最后每个有效测试都有48个坐标。
我不确定这是不对的。
Lee
I''d definitely appreciate it. In fact, I''m trying to find a decent
sphere version, and getting nowhere with google. I tried to figure it
out on my own, and ended up with 48 coordinates for each valid test.
I''m not sure if that''s right.
Lee
Em S ?? b，2006-04-08？* s 21:17 - 0700，Pythor escreveu：
Em S??b, 2006-04-08 ?*s 21:17 -0700, Pythor escreveu:
John Machin写道：
John Machin wrote:
（3）易读性：绝对
最小空间数的剧本没有奖品字符： - ）
(3) legibility: there''s no prize for the script with the absolutely
minimum number of space characters :-)
是的。我假设你说我应该制作cx，cy，dx和dy更好的名字。我可能会。到目前为止，我只是在玩这个，并没有真正期待其他人阅读它。
True. I assume your saying I should make cx,cy,dx, and dy better
names. I probably will. Up to now I was just playing around with
this, and not really expecting anyone else to read it.
这有点好笑，因为你刚发布了代码到一个列表与
数百名开发人员。 =）
-
Felipe。
This is kinda funny because you just posted the code to a list with
hundreds of developers. =)
--
Felipe.
这篇关于更多的pythonic圈？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
