解析工程符号 [英] parsing engineering symbols
问题描述
我想将字符串转换为浮点值。该字符串包含
工程符号。
例如,
s ='''12k''
>
我想要一些功能可以返回12000
功能
=> 12000.0
我在网上搜索,但找不到任何功能。
问候,
Suresh
类似于:
def cvt(输入):
如果输入.lower() .endswith(''k''):return float(输入[: - 1])* 1000
Suresh Jeevanandam写道:< blockquote class =post_quotes>
我想将字符串转换为浮点值。该字符串包含
工程符号。
例如,
s ='''12k''
我想要一些能返回12000的函数/> function(s)
=> 12000.0
我在网上搜索,但找不到任何功能。
问候,
Suresh
port this this
http://api.rubyonrails。 com / classes / A ... ric / Bytes.html
On Tue,2005年12月20日19:07:02 +0530, Suresh Jeevanandam< jm ******* @ gmail.com>写道:
我想将字符串转换为浮点值。该字符串包含
工程符号。
例如,
s ='''12k''
我想要一些能返回12000的函数/> function(s)
=> 12000.0
我搜索了网页,但找不到任何功能。
它应该很容易,如果你能准确定义什么
" ;包含工程符号意味着;-)
问候,
Bengt Richter
Hi,
I want to convert a string to float value. The string contains
engineering symbols.
For example,
s = ''12k''
I want some function which would return 12000
function(s)
=> 12000.0
I searched the web, but could not find any function.
regards,
Suresh
Something like:
def cvt(input):
if input.lower().endswith(''k''): return float(input[:-1])*1000
Suresh Jeevanandam wrote:Hi,
I want to convert a string to float value. The string contains
engineering symbols.
For example,
s = ''12k''
I want some function which would return 12000
function(s)
=> 12000.0
I searched the web, but could not find any function.
regards,
Suresh
port this
http://api.rubyonrails.com/classes/A...ric/Bytes.html
On Tue, 20 Dec 2005 19:07:02 +0530, Suresh Jeevanandam <jm*******@gmail.com> wrote:
Hi,
I want to convert a string to float value. The string contains
engineering symbols.
For example,
s = ''12k''
I want some function which would return 12000
function(s)
=> 12000.0
I searched the web, but could not find any function.
It should be easy enough, if you can define precisely what
"contains engineering symbols" means ;-)
Regards,
Bengt Richter
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