将从new返回的地址分配给引用 [英] Assigning the address returned from new to a reference

问题描述

我可以写：


T i& = new T;


谢谢!!!

Can I write:

T i&=new T;

Thanks!!!

推荐答案

Protoman schrieb：

Protoman schrieb:

我可以写一下：
T i& = new T;

Can I write:
T i&=new T;

当然你可以写这个;但没有conformat编译器会接受这个。而且我认为这不是你想问的问题;

我想你想问一下这样的事情......


T& t = *新的T（）;


....是合法的。它是！

Of course you can write this; but no conformat Compiler will
accept that. And I think its not the thing you wanted to ask;
I think you wanted to ask if something like ...

T &t = *new T();

.... is legal. It is!

Protoman写道：

Protoman wrote:

我可以写：

T i& = new T;

谢谢!!!

Can I write:

T i&=new T;

Thanks!!!

我想你的意思是

T& i = new T;


为什么你不写一个小程序看看会发生什么？

I think you meant
T &i = new T ;

Why don''t you write a small program and see what happens ?

" Oliver S." <佛******* @ gmx.net>在消息中写道

news：43 *********************** @ newsread2.arcor-online.net ...

"Oliver S." <Fo*******@gmx.net> wrote in message
news:43***********************@newsread2.arcor-online.net...

Protoman schrieb：

Protoman schrieb:

我可以写：
T i& = new T;

Can I write:
T i&=new T;

当然你可以写这个;但没有conformat Compiler会接受这个。而且我认为这不是你想问的问题;
我想你想问一下这样的事情......

T& t = * new T（）;

......是合法的。它是！

Of course you can write this; but no conformat Compiler will
accept that. And I think its not the thing you wanted to ask;
I think you wanted to ask if something like ...

T &t = *new T();

... is legal. It is!

你会如何删除它？

我不相信你可以删除引用，是吗？我不相信

删除t

会编译（虽然我可能会测试并查看）

How would you delete it?
I don''t believe you can delete a reference, can you? I don''t believe
delete t
would compile (although I might test it and see)

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