当我进入'（'只有程序说它是balanec !!!! [英] when I entered '(' only the program said it is balanec !!!!

问题描述

我已经完成了我的工作：


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在一个程序中使用Stack类，该程序读取一个字符串，一次一个字符，并确定该字符串是否包含平衡括号。也就是说，对于每个左括号（如果有的话），后面的字符串中只有一个匹配的右括号。


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//Stack.h

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解决方案

纠正这个for循环

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< blockquote>当我改变循环时，该函数只需要一个字符来测试它，我想要的是填充堆栈并看到''（''和''）''是否平衡...






我不知道如何用这项工作来完成字符串..我认为我不需要它因为我有char而不是它..是我的想法？

当我改变循环时，该函数只需要一个字符来测试它，我是什么想要填充堆栈，看看''（''和''）''是否平衡..

???你是什​​么意思只需要1个字符来测试它？你使用堆栈的方式，当你到达一致（平衡）字符串的末尾时，它保证是空的。它只会包含字符''（''并且只有在没有匹配的'''''时才会出现。

我不知道知道我怎么能用这项工作做字符串..我认为我不需要它因为我有char而不是它..我的想法是对的吗？

只要您只对测试数据感兴趣而不存储它以便以后使用它，那么使用char就可以了。如果您在输入后必须使用该字符串，那么您需要在某处存储字符输入，如字符串。

I have finshed my work on :

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Use the Stack classes in a program that reads a string, one character at a time, and determines whether the string contains balanced parentheses. That is, for each left parenthesis (if there are any) there is exactly one matching right parenthesis later in the string.

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//Stack.h

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解决方案

Correct this for loop

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when I changed the loop the function takes only one charcter to test it , what i want is to fill the stack and see is the ''('' and '')'' are balanced or not ..







I do not know how can I do the string with this work .. I think that I do not need it because I have "char" instead of it .. is my think right ?

when I changed the loop the function takes only one charcter to test it , what i want is to fill the stack and see is the ''('' and '')'' are balanced or not ..

??? what do you mean only takes 1 character to test it? The way you are using your stack it is guaranteed to be empty by the time you have go to the end of a conforming(balanced) string. It will only ever contain the character ''('' and only if it does not have a matching '')''.

I do not know how can I do the string with this work .. I think that I do not need it because I have "char" instead of it .. is my think right ?

As long as you are only interested in testing the data and not storing it to use it later then using a char is fine. If you are going to have to use the string once it has been input then you will need somewhere to store the characters input, like a string.

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