Python类型 [英] Python types

问题描述

您好，


我已经阅读了几篇文章，其中说Python的类型很弱。

我有点惊讶。所有物品似乎都有一个完美的定义

类型


我错了吗？


问候

Hello,

I''ve read several articles where it''s said that Python is weakly typed.
I''m a little surprised. All objects seem to have a perfectly defined
type

Am i wrong?

Regards

推荐答案

我认为这意味着名字，而不是对象，是弱类型的。所以你可以

有：

a = 4

a =''你好''


和没有问题。 a这个名字并没有与它相关的任何类型

。这与像C这样的强类型语言形成鲜明对比，如果你试图分配一个值，那么你需要在b / b
编译时声明名称（变量）和编译器对象的类型。另一种类型。

I think it means that names, not objects, are weakly typed. So you can
have:
a = 4
a = ''hello''

and there is no problem. The name ''a'' doesn''t have any type associated
with it. This contrasts with strongly typed language like C where you
declare the type of the name (variable) and the compiler objects at
compile time if you attempt to assign a value of a different type.

Steve M schrieb：

Steve M schrieb:

我认为这意味着名字而不是对象是弱类型的。所以你可以：
a = 4
a =''你好''

并且没有问题。 a这个名字并没有与之相关的任何类型。这与C之类的强类型语言形成对比，如果您尝试分配不同类型的值，则在编译时声明名称（变量）的类型和编译器对象。

I think it means that names, not objects, are weakly typed. So you can
have:
a = 4
a = ''hello''

and there is no problem. The name ''a'' doesn''t have any type associated
with it. This contrasts with strongly typed language like C where you
declare the type of the name (variable) and the compiler objects at
compile time if you attempt to assign a value of a different type.

void foo（）{

int * c =" hello weakly typed C！" ;;

}

192：/ tmp deets

void foo() {
int *c = "hello weakly typed C!";
}
192:/tmp deets

gcc -c test.c

test.c：在函数`foo''：

test.c：5：警告：从不兼容的指针类型初始化


所以我不会叫C强类型....


区别通常在两个轴上进行：强弱和

静态动态。 Python是一种强类型的动态语言。 JAVA是

强类型静态。 PHP是弱类型的动态。


问候，


Diez

gcc -c test.c
test.c: In function `foo'':
test.c:5: warning: initialization from incompatible pointer type

So I wouldn''t call C strongly typed....

The distinction is usually made on two axis: strong-weak and
static-dynamic. Python is a strong-typed, dynamic language. JAVA is
strong-typed static. And PHP is weakly-typed dynamic.

Regards,

Diez

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