为什么这个xpath会失败？ [英] Why does this xpath fail?

问题描述

XPathNavigator nav = MyCreateNav（）; // InnerXml ==" software"

nav.SelectSingleNode"。[。=''software'']"）;


select返回例外：

+ $例外{"''。[。='''软件'''''有一个无效的令牌。"} System.Exception

{System.Xml.XPath.XPathException}


知道为什么吗？


-

谢谢 - 戴夫

david_at_windward_dot_net
http://www.windwardreports.com

解决方案

exception {"''。[。=''software'']''的令牌无效。 "} System.Exception

{System.Xml.XPath.XPathException}


知道为什么吗？


-

谢谢 - 戴夫

david_at_windward_dot_net
http://www.windwardreports.com

David Thielen写道：

XPathNavigator nav = MyCreateNav（）; // InnerXml ==" software"
nav.SelectSingleNode"。[。=''software'']"）;

^^^^^^

这在语法上是不正确的C＃所以首先发布实际代码

然后我们可以讨论XPath表达式。

-


Martin Honnen --- MVP XML
http：// JavaScript.FAQTs.com/

抱歉 - 放弃了（


XPathNavigator nav = MyCreateNav（）; / / InnerXml ==" software"

nav.SelectSingleNode（&。; [。=''software'']"）;


-

谢谢 - 戴夫

david_at_windward_dot_net
http://www.windwardreports.com


" Martin Honnen"写道：

XPathNavigator nav = MyCreateNav（）; // InnerXml ==" software"
nav.SelectSingleNode"。[。=''software'']"）;

^^^^^^
那甚至语法都不正确C＃所以首先发布实际代码
然后我们可以讨论XPath表达式。

-

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/

XPathNavigator nav = MyCreateNav(); // InnerXml == "software"
nav.SelectSingleNode".[.=''software'']");

The select returns an exception:
+ $exception {"''.[.=''software'']'' has an invalid token."} System.Exception
{System.Xml.XPath.XPathException}

Any idea why?

--
thanks - dave
david_at_windward_dot_net
http://www.windwardreports.com

解决方案

exception {"''.[.=''software'']'' has an invalid token."} System.Exception
{System.Xml.XPath.XPathException}

Any idea why?

--
thanks - dave
david_at_windward_dot_net
http://www.windwardreports.com

David Thielen wrote:

XPathNavigator nav = MyCreateNav(); // InnerXml == "software"
nav.SelectSingleNode".[.=''software'']");

^^^^^^
That is not even syntactically correct C# so first post the real code
then we can discuss the XPath expression.
--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/

Sorry - dropped a (

XPathNavigator nav = MyCreateNav(); // InnerXml == "software"
nav.SelectSingleNode(".[.=''software'']");

--
thanks - dave
david_at_windward_dot_net
http://www.windwardreports.com

"Martin Honnen" wrote:

David Thielen wrote:

XPathNavigator nav = MyCreateNav(); // InnerXml == "software"
nav.SelectSingleNode".[.=''software'']");

^^^^^^
That is not even syntactically correct C# so first post the real code
then we can discuss the XPath expression.
--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/

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