唯一名称生成 [英] Unique Name Generation
问题描述
我需要能够为文件生成唯一的名称。我正在考虑使用哈希算法，但是如果我有两个同名文件，我会得到相同哈希的
。我正在收集和存储文件，我想将它们存储在同一目录中，并且我希望这些名称具有神秘性和独特性。
有什么想法吗？
Jerry
I need to be able to generate unique names for files. I was considering
that hash alogorithms, but if I had two files with the same name, I''d get
the same hash. I am collecting and storing files and I want to store them
all in the same directory and I want the names to be cryptic and unique.
Any thoughts?
Jerry
推荐答案
Jerry Camel写道：
Jerry Camel wrote:
我需要能够生成文件的唯一名称。我是在考虑哈希算法，但如果我有两个同名的文件，我会得到相同的哈希值。我正在收集和存储文件
我希望将它们存储在同一目录中，我希望
名称具有神秘性和独特性。有什么想法吗？
I need to be able to generate unique names for files. I was
considering that hash alogorithms, but if I had two files with the
same name, I''d get the same hash. I am collecting and storing files
and I want to store them all in the same directory and I want the
names to be cryptic and unique. Any thoughts?
我需要在VB3 / 8.3时代进行图像采集程序。
有可能有很多在任何给定的
天，来自许多计算机的图像，所以我想出了类似这样的base-36命名系统。 BTW，
它已经很久以前所以请不要因为数学错误而惹火。 < g>
基本36代码：
0 = 0
1 = 1
....
9 = 9
A = 10
B = 11
......
Z = 36
8.3文件名的8部分是这种形式：
YMDZZXXX
Y - 年。 0 = 1990,1 = 1991，...，Z =（1990 + 36）
M - 月。 1 = 1月1日，2月= 2月，...（基于1 - 便于阅读）
D - 第1天= 1，...（基于1 - 便于阅读） />
ZZ - 指定的计算机编号 36 * 36种可能性
XXX - 序列＃。 36 * 36 * 36种可能性
该程序在ini文件中查找当天的下一个序列＃
生成了8.3文件名的8部分，检查目录，如果已经
存在增量&再次尝试，反复直到ZZZ + 1失败，
保存完整的8.3（JPG，TIF，WSQ或BMP），更新了ini文件。
它运作良好。在1990年代中期拍摄的图像仍然是
指纹生物识别测试数据库的一部分，我相信。
我认为它会满足你的需求。神秘而独特的要求。 < g>
- Mark
I needed to do this in the VB3 / 8.3 era for an image capture program.
There was the possibility of many images from many computers on any given
day, so I came up with a base-36 naming system something like this. BTW,
it''s been a long time ago so please don''t flame for math errors. <g>
Base 36 code:
0 = 0
1 = 1
....
9 = 9
A = 10
B = 11
....
Z = 36
The 8 part of the 8.3 filenames were of this form:
YMDZZXXX
Y -- Year. 0 = 1990, 1=1991, ..., Z = (1990 + 36)
M -- Month. 1 = Jan, 2 = Feb, ... (1-based for ease of reading)
D -- Day 1 = 1, ... (1-based for ease of reading)
ZZ -- "Assigned Computer Number" 36 * 36 possibilities
XXX -- Sequence #. 36 * 36 * 36 possibilities
The program looked in an ini file for the next sequence # for that day,
generated the 8 part of the 8.3 filename, checked the directory, if already
existed incremened & tried again, repeatedly until ZZZ+1 before failing,
saved the full 8.3 (JPG, TIF, WSQ or BMP), updated the ini file.
It worked well. Images captured in the mid 1990''s are still part of a
fingerprint biometric test database, I believe.
I think it would satisfy your "cryptic and unique" requirements. <g>
-- Mark
Mark Jerde写道：
Mark Jerde wrote:
顺便说一句，这是很久以前所以请不要因为数学错误而惹火。 < g取代;
或者程序员内存错误要么...... ;-)我现在回忆起它有点儿了，但是b $ b更加神秘。我使用前7个字符来定义家庭字符。的文件，所有
在相同的注册中。第八个字符指定了哪个图像和
印象，即Face，Right Profile＃2。或右手食指，第三次
印象。第八个字符代表的内容保存在一个ini文件中
命名为前7个字符.TXT。
8.3文件名的8个部分是这种形式的：
YMDZZXXX
BTW, it''s been a long time ago so please don''t flame for math
errors. <g>
Or programmer memory errors either... ;-) I recall now it was a little
more cryptic. I used the first 7 chars to define a "family" of files, all
in the same "enrollment." The eighth character specified which image and
impression, ie "Face, Right Profile #2" or "Right Index Finger, 3rd
impression." What the eighth character stood for was saved in a ini file
named the first 7 chars .TXT.
The 8 part of the 8.3 filenames were of this form:
YMDZZXXX
差不多。应该是
YMDZZXXA
XX - 序列＃。 36 * 36种可能性
A - 哪个图像代号。 36个可能性。保存在
的家庭中.TXT文件。
FWIW ...< G>
- Mark
" Jerry Camel" < RL ***** @ msn.com>写在
新闻：eM ************* @ tk2msftngp13.phx.gbl：
"Jerry Camel" <rl*****@msn.com> wrote in
news:eM*************@tk2msftngp13.phx.gbl:
我需要能够生成文件的唯一名称。
I need to be able to generate unique names for files.
使用GUID。它们保证是独一无二的，而且它们是神秘的。生成GUID的最简单方法是从$ / b $ b请求WinAPI中的一个：
--clip--
私有类型GUID
Data1 As Long
Data2 As Integer
Data3 As Integer
Data4（7）As Byte
结束类型
私有声明功能CoCreateGuid Lib" OLE32.DLL" _
（pGuid作为GUID）长期
私函数GetGUID（）字符串
Dim udtGUID作为GUID
如果（CoCreateGuid（udtGUID）= 0）那么
GetGUID = _
字符串（8 - Len（Hex
Use GUIDs. They are guaranteed to be unique, and they
are cryptic. Easiest way to generate a GUID is to
ask for one from WinAPI:
--clip--
Private Type GUID
Data1 As Long
Data2 As Integer
Data3 As Integer
Data4(7) As Byte
End Type
Private Declare Function CoCreateGuid Lib "OLE32.DLL" _
(pGuid As GUID) As Long
Private Function GetGUID() As String
Dim udtGUID As GUID
If (CoCreateGuid(udtGUID) = 0) Then
GetGUID = _
String(8 - Len(Hex
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