Perl模式匹配 [英] Perl pattern matching

问题描述

我有一串字符ex：fhjhejfherhfehkehkeh


我想保留第一个h并删除所有其他字符我该怎么办？

I have a string of characters ex: fhjhejfherhfehkehkeh

I want to retain the first "h" and delete all the other characters how do i do it ?

推荐答案

到目前为止你尝试了什么？我们希望看到你走的路，而不仅仅是给你代码。这是一种更好的学习方式。那么，我们可以指导你。


问候，


杰夫

What have you tried thus far? We would like to see what road you are going down instead of just giving you the code. Its a better way to learn. Then, we can guide you.

Regards,

Jeff

从我开始perl的一个新手。

我知道如何删除第一个？h？字符并保持原样，使用^

但我想知道如何我做的反过来就是保持第一个？h？字符并删除剩余的h字符。字符

To start with i am a newbie in perl.
I am aware of how to delete the first ?h ?character and keep the remaining as it is, using ^
But I wanted to know how I do the inverse of this i.e keep the first ?h? character and remove the remaining "h" characters

正则表达式：s /(.* h [^ h] *）h /

regex: s/(.*h[^h]*)h/

这篇关于Perl模式匹配的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！