只有一点回报 [英] Only one point of return
问题描述
一位同事告诉我，有一个关于良好类型的规则，C ++中的一个
函数应该只有一个返回点（即返回
语句）。否则可能会有麻烦。
我从来没有听说过它并对此表示怀疑。
是否有人听说过它？有什么好处？
问候，
Marc
例如：
bool f（）
{
如果（！pointer1）返回false;
pointer1-> doSomething（）;
if（！pointer2）返回false;
pointer2-> doSomething1（）;
返回true ;
}
vs.
bool f（）
{
bool retVal = true;
if（pointer1）
{
pointer1-> doSomething（）; < br $>
}
其他
retVal = false;
if（pointer2）
{
pointer2-> doSomething（）;
}
else
retVal = false;
返回retVal;
}
A colleague told me that there is a rule about good stype that a
function in C++ should have only one point of return (ie. return
statement). Otherwise there might be trouble.
I never heard about it and doubt it.
Anybody heard of it? What would be the advantage?
Regards,
Marc
Example:
bool f()
{
if( !pointer1) return false;
pointer1->doSomething();
if( !pointer2) return false;
pointer2->doSomething1();
return true;
}
vs.
bool f()
{
bool retVal=true;
if( pointer1)
{
pointer1->doSomething();
}
else
retVal=false;
if( pointer2)
{
pointer2->doSomething();
}
else
retVal=false;
return retVal;
}
推荐答案
< a href =mailto：cp ******** @ googlemail.com> cp ******** @ googlemail.com 写道：
一位同事告诉我，有一条关于善的规则在C ++中使用
函数应该只有一个返回点（即。返回
声明）。否则可能会有麻烦。
我从来没有听说过它并对此表示怀疑。
是否有人听说过它？有什么好处？
A colleague told me that there is a rule about good stype that a
function in C++ should have only one point of return (ie. return
statement). Otherwise there might be trouble.
I never heard about it and doubt it.
Anybody heard of it? What would be the advantage?
这是一个相当常见的编码标准。
在我看来，它更有意义C比C ++，只要你的代码是
异常安全，早期退货不应该造成任何伤害。有些人可能认为
单点返回会使调试变得更容易。
C或C ++早期返回的常见问题并非例外
安全是资源泄漏，有问题的资源只在功能结束时或最后一次返回之前发布
。
-
Ian Collins。
It is a fairly common coding standard.
In my opinion it makes more sense for C than C++, provided your code is
exception safe an early return shouldn''t do any harm. Some may argue
that a single point of return makes debugging easier.
A common problem early returns with either C or C++ that isn''t exception
safe is resource leaks where the resource in question is only released
at the end of the function or before the last return.
--
Ian Collins.
< cp ******** @ googlemail .comwrote in message
news：11 ********************** @ o61g2000hsh.googlegr oups.com ...
<cp********@googlemail.comwrote in message
news:11**********************@o61g2000hsh.googlegr oups.com...
>一位同事告诉我，有一个关于良好类型的规则，C ++中的
函数应该只有一个返回点（即。返回
声明）。否则可能会有麻烦。
我从来没有听说过它并对此表示怀疑。
是否有人听说过它？有什么好处？
问候，
Marc
例如：
bool f（）
{
如果（！pointer1）返回false;
pointer1-> doSomething（）;
if（！pointer2）返回false;
pointer2-> doSomething1（）;
返回true ;
}
vs.
bool f（）
{
bool retVal = true;
if（pointer1）
{
pointer1-> doSomething（）; < br $>
}
其他
retVal = false;
if（pointer2）
{
pointer2-> doSomething（）;
}
else
retVal = false;
返回retVal;
}
>A colleague told me that there is a rule about good stype that a
function in C++ should have only one point of return (ie. return
statement). Otherwise there might be trouble.
I never heard about it and doubt it.
Anybody heard of it? What would be the advantage?
Regards,
Marc
Example:
bool f()
{
if( !pointer1) return false;
pointer1->doSomething();
if( !pointer2) return false;
pointer2->doSomething1();
return true;
}
vs.
bool f()
{
bool retVal=true;
if( pointer1)
{
pointer1->doSomething();
}
else
retVal=false;
if( pointer2)
{
pointer2->doSomething();
}
else
retVal=false;
return retVal;
}
第二个例子不同于第一个例子
它会转到指针2部分，即使指针1不存在
。
每个人都有一个意见，但是在C ++中有IMO，维持
a单身入口点导致更多混淆代码
而不是更少（这是，我相信，
支持它的论点。）
This second example is different than the first since
it goes to the pointer2 part even if pointer1 doesn''t
exist.
Everyone has an opinion but IMO in C++, maintaining
a single entry point leads to more obfuscated code
rather than less (which is, I believe, the argument in
favor of it.)
" duane hebert" < sp ** @flarn.comwrote in message
news：9p ******************** @ weber.videotron.net .. 。
"duane hebert" <sp**@flarn.comwrote in message
news:9p********************@weber.videotron.net...
第二个例子与第一个例子不同，因为
即使指针1不是
存在。
每个人都有意见，但IMO在C ++中，保持单个入口点
a导致更多混淆代码
This second example is different than the first since
it goes to the pointer2 part even if pointer1 doesn''t
exist.
Everyone has an opinion but IMO in C++, maintaining
a single entry point leads to more obfuscated code
a单出口点（duh）
a single exit point (duh)
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