请帮助解决错误 [英] help with an error please
问题描述
我正在尝试测试一个字符是否为输入字符。钥匙，我打算测试它
if（DataBits！= null）
{
stuff
}
就是这样，但我得到了
H：\> c：\ j2sdk1.4.1 \ bin \ javac.exe BubbleSort.java
BubbleSort.java:68：operator！=无法应用于char，< nulltype>
if（DataBits！= null）
^
1错误
如果你能提交一个相当简单的解决方案，我将非常高兴，提前感谢您的时间。
Steve
I am trying to test a character for being the "Enter" key, I figured to test it
if(DataBits!=null)
{
stuff
}
like that, but i got
H:\>c:\j2sdk1.4.1\bin\javac.exe BubbleSort.java
BubbleSort.java:68: operator != cannot be applied to char,<nulltype>
if(DataBits!=null)
^
1 error
if you could please submit a reasonably simple solution I would be very happy, thanks ahead of time for your time.
Steve
推荐答案
输入键难道不能产生换行符吗？然后你可以检查
Shouldn''t the enter key produce a newline character? Then you can check
我正在尝试测试角色是否为输入钥匙，我打算测试它
if（DataBits！= null）
{
stuff
}
就是这样，但我得到了
H：\> c：\ j2sdk1.4.1 \ bin \ javac.exe BubbleSort.java
BubbleSort.java:68：operator！=无法应用于char，< nulltype>
if（DataBits！= null）
^
1错误
如果你能提交一个相当简单的解决方案，我将非常高兴，提前感谢您的时间。
Steve
I am trying to test a character for being the "Enter" key, I figured to test it
if(DataBits!=null)
{
stuff
}
like that, but i got
H:\>c:\j2sdk1.4.1\bin\javac.exe BubbleSort.java
BubbleSort.java:68: operator != cannot be applied to char,<nulltype>
if(DataBits!=null)
^
1 error
if you could please submit a reasonably simple solution I would be very happy, thanks ahead of time for your time.
Steve
亲爱的。你现在想做什么JavaStudent？
只要解释你想要达到的目标，我肯定有一种简单的方法。
Oh dear. What are you trying to do now JavaStudent?
Just explain what you want to achieve and I''m sure there is a simple way of doing it.
与之前lol相同的程序，三个月，如果那个XD jeez lol可能会带给你们一个......哦，非常感谢你的提示：）
the same program as before lol, three months, probably take you guys one if that XD jeez lol...oh well thanks for the tip :)
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