sed awk或perl为此？ [英] sed awk or perl for this?

问题描述

我有一个输出以下内容的脚本。


200 23.131.155.5;

1 23.131.161.4;

2 102.131.161.54;

2 23.160.180.4;

35 54.1.8.7;

356 15.18.235.52;

1 205.18.235.88;

1 205.18.246.21;

1 205.18.247.121;

9 207.89.177.202;

6 27.89.177.234;

2 208.7.71.85;

1 23.3.17.30;

4 210.92.146.15;

2 21.126.142.17;

3 22.180.255.20;

第一列是no。第2栏中的主持人做过的时间

不应该做的事情。我只需要看到主人

做了很多不好的事情而不是一两次所以我是

寻找像这样的东西。


../scripts.sh | < somecommand过滤并向我显示的行是

的第一列多于一个字符。>


200 23.131.155.5;

35 54.1.8.7;

356 15.18.235.52;


任何想法？

谢谢。

I have a script that outputs the following.

200 23.131.155.5;
1 23.131.161.4;
2 102.131.161.54;
2 23.160.180.4;
35 54.1.8.7;
356 15.18.235.52;
1 205.18.235.88;
1 205.18.246.21;
1 205.18.247.121;
9 207.89.177.202;
6 27.89.177.234;
2 208.7.71.85;
1 23.3.17.30;
4 210.92.146.15;
2 21.126.142.17;
3 22.180.255.20;
The first colums is the no. of time a host in column 2 has did
something that is was not supposed to do. I only need to see hosts
that did bad things significant times not one or two time so I am
looking for somehthing like this.

../scripts.sh | <somecommand that filters and just show me lines that
has first colum more then one char.>

200 23.131.155.5;
35 54.1.8.7;
356 15.18.235.52;

any ideas?
Thanks.

推荐答案

2003年9月11日06:48:06 -0700， ne******@yahoo.com （NNTP）写道：

On 11 Sep 2003 06:48:06 -0700, ne******@yahoo.com (NNTP) wrote:

第一列是no。第2列中的主持人所做的事情是不应该做的事情。我只需要看到那些做过不好事的主人，而不是一两次，所以我在寻找像这样的东西。
任何想法？

The first colums is the no. of time a host in column 2 has did
something that is was not supposed to do. I only need to see hosts
that did bad things significant times not one or two time so I am
looking for somehthing like this. any ideas?

我不知道sed或awk，但是：


perl -e ''while（<>）

{（

I don''t know sed or awk, but:

perl -e ''while (<>)
{ (

num，

ip）= split;下一个if（

ip)=split; next if (

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