帮助Lvalue需要问题 [英] Help Problem with Lvalue required
问题描述
你好我有我的代码，但有问题char = char
#include< conio.h>
#include< stdio。 h>
struct Pate {
char Nome [20];
};
main （）
{
char lettere [3] = {''A''，''P''，''Z''};
Pate articoli [3] = {{" gli"}，{" un"}，{" una"}};
Pate
preposizioni [10] = {{"二"}，{" A"}，{" DA"}，{"在"}，{" CON"}，{"苏"}，{"每" }，{" tra"}，
{" fra"}};
char text [5000]，pat [100]，te [ 1];
int no，count，pos [20]，i;
clrscr（）;
cout<<"" \\ n \ n插入文字：" ;;
得到（文字）;
cout<<"插入一个字符串：" ;;
//得到（拍）;
for（i = 0; i< 3; i ++）{
// pat = lettere [i] ; //错误
pat = articoli [1] .Nome; //错误
}
}
Maurizio Porcu写道：你好，我有我的代码，但有问题char = char
不，你有char [] = char []的问题。你可能会发现它很容易使用std :: string。
＃include< conio.h>
#include< stdio。 h取代;
conio.h不标准。 stdio.h适用于C. C ++应该使用< cstdio>或者
更好< iostream> ;.
struct Pate {
char Nome [20];
};
怎么样 ：
typedef char Nome [20];
或更好：
#include< string>
main（）
int main（ ）
{
char lettere [3] = {''A''，''P''，''Z''};
Pate articoli [3] = {{" gli"}，{" un"}，{" una"}};
Pate
preposizioni [10] = {{" di"}，{" a" }，{" DA"}，{"在"}，{" CON"}，{"苏"}，{"每" }，{" tra"}，
{" fra"}};
将这些都设为const。
char text [5000]，pat [100]，te [1];
一个数组？
int no，count，pos [20]，i;
clrscr（）;
非标准。
cout<<" \ n \ n插入文字：" ;;
获取（文字）;
你在混合cout（当你实际上并没有包括< iostream>！）和
得到？喜欢cin得到。
cout<<"插入一个字符串：" ;;
//获取（pat）;
for（i = 0; i< 3 ; i ++）{
// pat = lettere [i]; //错误
pat = articoli [1] .Nome; //错误
使用std :: string来获得这种便利。否则，你需要
来包含< string.h>或< cstring>得到strcpy。
}
返回0;
}
干杯！ --M
Maurizio Porcu写道：你好，我有这个我的代码，但有char = char $ b $的问题b
不，你不是。你有char [] = char []的问题。
#include< conio.h>
#include< stdio.h>
struct Pate {
char Nome [20];
};
main（）
int main（）
{
char lettere [3] = {''A''，''P''，''Z''};
Pate articoli [3] = {{" gli"}，{" ; un"}，{" una"}};
Pate
preposizioni [10] = {{" di"}，{" a"}，{" da"}，{ "在"}，{" CON"}，{"苏"}，{"每" }，{" tra"}，
{" fra"}};
char text [5000]，pat [100]，te [1];
int no，count，pos [20]，i;
clrscr（）;
cout<<" \ n \ n插入文字：" ;;
获取（文字）;
cout<<"插入一个字符串：" ;;
//获取（pat）;
for（i = 0; i< 3; i ++）{
// pat = lettere [i]; //错误
pat = articoli [1] .Nome; //错误
数组不能用C ++分配
}
}
不要使用字符数组，请使用''std :: string''。
V
给我推荐pelase
i学生并且需要解决这个问题
" Victor Bazarov" <五******** @ comAcast.net> ha scritto nel messaggio
新闻：oT ******************* @ newsread1.mlpsca01.us.t o.verio.net ...Maurizio Porcu写道：你好我有这个我的代码但是有问题char = char
不，你不要T。你有char [] = char []的问题。
#include< conio.h>
#include< stdio.h>
struct Pate {
char Nome [20];
};
main（）
int main（）
< blockquote class =post_quotes> {
char lettere [3] = {''A''，''P''，''Z''};
Pate articoli [3] = {{ " gli"}，{" un"}，{" una"}};
Pate
preposizioni [10] = {{" di"}，{"一个"}，{" DA"}，{"在"}，{" CON"}，{"苏"}，{"每" }，{" tra"}，{" fra"}};
char text [5000]，pat [100]，te [1];
int no，count， pos [20]，i;
clrscr（）;
cout<<" \ n \ n插入文字：" ;;
获取（文字）;
cout<<"插入一个字符串：" ;;
//获取（pat）;
for（i = 0; i< 3; i ++）{
//轻拍=莱泰雷[I]; //错误
pat = articoli [1] .Nome; //错误
数组不能在C ++中分配
}
}
不要使用字符数组，使用''std :: string''。
V
Hello i have this my code but have problem with char=char
# include <conio.h>
# include <stdio.h>
struct Pate {
char Nome[20];
};
main()
{
char lettere[3] = { ''A'',''P'',''Z''};
Pate articoli[3]={{"gli"},{"un"},{"una"}};
Pate
preposizioni[10]={{"di"},{"a"},{"da"},{"in"},{"con"},{"su"},{"per" },{"tra"},
{"fra"}};
char text[5000],pat[100], te[1];
int no,count,pos[20],i;
clrscr();
cout<<"\n\nInsert text:";
gets(text);
cout<<"Insert one string:";
// gets(pat);
for (i=0;i<3;i++){
//pat=lettere[i]; //error
pat=articoli[1].Nome; //error
}
}
Maurizio Porcu wrote:Hello i have this my code but have problem with char=char
No, you have a problem with char[] = char[]. You''ll probably find it
easier to work with std::string.
# include <conio.h>
# include <stdio.h>
conio.h is not standard. stdio.h is for C. C++ should use <cstdio> or
better <iostream>.
struct Pate {
char Nome[20];
};
How about:
typedef char Nome[20];
or better:
#include <string>
main()
int main()
{
char lettere[3] = { ''A'',''P'',''Z''};
Pate articoli[3]={{"gli"},{"un"},{"una"}};
Pate
preposizioni[10]={{"di"},{"a"},{"da"},{"in"},{"con"},{"su"},{"per" },{"tra"},
{"fra"}};
Make these all const.
char text[5000],pat[100], te[1];
An array of one?
int no,count,pos[20],i;
clrscr();
Non-standard.
cout<<"\n\nInsert text:";
gets(text);
You''re mixing cout (when you didn''t actually include <iostream>!) and
gets? Prefer cin to gets.
cout<<"Insert one string:";
// gets(pat);
for (i=0;i<3;i++){
//pat=lettere[i]; //error
pat=articoli[1].Nome; //error
Use std::string to get this type of convenience. Otherwise, you''ll need
to include <string.h> or <cstring> to get strcpy.
}
return 0;
}
Cheers! --M
Maurizio Porcu wrote:Hello i have this my code but have problem with char=char
No, you don''t. You have a problem with char[]=char[].
# include <conio.h>
# include <stdio.h>
struct Pate {
char Nome[20];
};
main()
int main()
{
char lettere[3] = { ''A'',''P'',''Z''};
Pate articoli[3]={{"gli"},{"un"},{"una"}};
Pate
preposizioni[10]={{"di"},{"a"},{"da"},{"in"},{"con"},{"su"},{"per" },{"tra"},
{"fra"}};
char text[5000],pat[100], te[1];
int no,count,pos[20],i;
clrscr();
cout<<"\n\nInsert text:";
gets(text);
cout<<"Insert one string:";
// gets(pat);
for (i=0;i<3;i++){
//pat=lettere[i]; //error
pat=articoli[1].Nome; //error
Arrays are not assignable in C++
}
}
Don''t use character arrays, use ''std::string''.
V
give me recommend pelase
i student and have need to solve this problem
"Victor Bazarov" <v.********@comAcast.net> ha scritto nel messaggio
news:oT*******************@newsread1.mlpsca01.us.t o.verio.net...Maurizio Porcu wrote:Hello i have this my code but have problem with char=char
No, you don''t. You have a problem with char[]=char[].# include <conio.h>
# include <stdio.h>
struct Pate {
char Nome[20];
};
main()
int main(){
char lettere[3] = { ''A'',''P'',''Z''};
Pate articoli[3]={{"gli"},{"un"},{"una"}};
Pate
preposizioni[10]={{"di"},{"a"},{"da"},{"in"},{"con"},{"su"},{"per" },{"tra"}, {"fra"}};
char text[5000],pat[100], te[1];
int no,count,pos[20],i;
clrscr();
cout<<"\n\nInsert text:";
gets(text);
cout<<"Insert one string:";
// gets(pat);
for (i=0;i<3;i++){
//pat=lettere[i]; //error
pat=articoli[1].Nome; //error
Arrays are not assignable in C++}
}
Don''t use character arrays, use ''std::string''.
V
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