返回类型比方法访问性低 [英] return type is less accessible than method

问题描述

我是新来的 C＃这里是从一个个人项目的摘录我的工作得到了一些经验。

在调用 getRecipe（）这个类以外的功能我是psented错误如下$ P $。我想保持我的列表私有的食谱类，但仍然能够获得一个参考的一个食谱的名单。我不想让我的列表公开。

任何意见大大AP preciated！谢谢

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错误

 返回类型cookbook.Recipe比方法进行访问少cookbook.CookBook.getRecipe（串）'
 

---

 公共类食谱
{
    私人列表＆LT;配方＆GT; listOfRecipes =新的名单，其中，配方＆GT; {};
    公方getRecipe（字符串名称）
    {
        INT I = 0;
        而（listOfRecipes [I] .getRecipeName（）！=名称）
        {
            我++;
        }
        返回listOfRecipes [I]
    }
}
 

解决方案

请在配方类上市。

I am new to c# and here is an excerpt from a personal project i am working on to get some experience.

When calling the getRecipe() function outside this class i am presented with the following error. I want to keep my List private to the CookBook class but still be able to get a reference to one of the Recipes in the List. I do not want to make my List public.

Any advice is greatly appreciated! Thanks

---

The error

return type 'cookbook.Recipe is less accessible than method 'cookbook.CookBook.getRecipe(string)'

---

public class CookBook
{
    private List<Recipe> listOfRecipes = new List<Recipe> {};
    public Recipe getRecipe(string name)
    {
        int i = 0;
        while (listOfRecipes[i].getRecipeName() != name)
        {
            i++;
        }
        return listOfRecipes[i];
    }
}

解决方案

Make the Recipe class public.

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