std :: string和整数 [英] std::string and integers

问题描述

显然以下不起作用：


int i = 5;

std :: string myString =" Number is" + i +请大家祝你好！


所以有人能告诉我这种方式最好的方法吗？

我很有信心我没有使用sprintf。


感谢，

GA

解决方案

< blockquote>Glen Able < SM ************* @ hotMEmail.com>写道：

显然以下不起作用：
int i = 5;
std :: string myString =" Number is" + i +谢谢你，;
所以任何人都可以让我知道这种事情最好的方式是什么？
我确定它没有使用sprintf。

您可以使用cout样式格式打印到字符串。请参阅常见问题
http://www.parashift.com/c++-faq-lit....html#faq-38.1

2004年7月8日星期四，Glen Able写道：

显然以下不起作用：

int i = 5 ;
std :: string myString =" Number is" + i +请你好吗？

所以任何人都可以告诉我这种事情最好的方法是什么？
我确定它没有使用sprintf。

谢谢，
GA

//单程：


#include < sstream>

#include< string>

#include< iostream>

使用命名空间std;


int main（）

{

int i = 5;

string myString1 ="数字是 ;

string myString2 ="谢谢，请;


ostringstream os;


os<< myString1<< i<< myString2;

string msgString = os.str（）;


cout<< msgString<< endl;


}

试试

int i = 5;

std :: string myString;

myString =" Number is" + i +谢谢你，

// ANders

2004年7月8日星期四09:28:58 +0100，Glen Able写道：

显然以下不起作用：

int i = 5;
std :: string myString =" Number is" + i +请你好吗？

所以任何人都可以告诉我这种事情最好的方法是什么？
我确定它没有使用sprintf。

谢谢，
GA

Obviously the following doesn''t work:

int i = 5;
std::string myString = "Number is " + i + " thankyou please";

So can anyone give me some idea what''s the nicest way to this sort of thing?
I''m sure it''s not using sprintf.

with thanks,
G.A.

解决方案

"Glen Able" <sm*************@hotMEmail.com> writes:

Obviously the following doesn''t work: int i = 5;
std::string myString = "Number is " + i + " thankyou please"; So can anyone give me some idea what''s the nicest way to this sort of thing?
I''m sure it''s not using sprintf.

You can use cout-style formatting to print to a string. See the FAQ
http://www.parashift.com/c++-faq-lit....html#faq-38.1

On Thu, 8 Jul 2004, Glen Able wrote:

Obviously the following doesn''t work:

int i = 5;
std::string myString = "Number is " + i + " thankyou please";

So can anyone give me some idea what''s the nicest way to this sort of thing?
I''m sure it''s not using sprintf.

with thanks,
G.A.

// one way:

#include <sstream>
#include <string>
#include <iostream>
using namespace std;

int main()
{
int i = 5;
string myString1 = "The number is ";
string myString2 = " thank you, please";

ostringstream os;

os << myString1 << i << myString2;
string msgString = os.str();

cout << msgString << endl;

}

try
int i = 5;
std::string myString;
myString = "Number is " + i + " thankyou please";
// ANders
On Thu, 08 Jul 2004 09:28:58 +0100, Glen Able wrote:

Obviously the following doesn''t work:

int i = 5;
std::string myString = "Number is " + i + " thankyou please";

So can anyone give me some idea what''s the nicest way to this sort of thing?
I''m sure it''s not using sprintf.

with thanks,
G.A.

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