STL扩展 [英] STL extension
问题描述
您好。
我尝试扩展STL，例如，添加成员函数如trim_left到
basic_string< charT，traits，Alloc>。然而，我一旦绝望，我就会看到
STL来源。我正在使用STLport 5.0-0409和vc 6.0。
如何轻松扩展STL？任何帮助将不胜感激。谢谢。
Hello.
I try to extend STL, for example, add member function like trim_left to
basic_string<charT, traits, Alloc>. However I am in the despair as soon as I
see
STL source. I am using STLport 5.0-0409 with vc 6.0.
How can I extend STL easily? Any help will be appreciated. Thanks.
推荐答案
" Park Ho-Kyung" < IL **** @ eoneo.co.kr>在消息中写道
news：cf ********** @ news1.kornet.net ...
"Park Ho-Kyung" <il****@eoneo.co.kr> wrote in message
news:cf**********@news1.kornet.net...
你好。
我尝试扩展STL，例如，添加成员函数如trim_left到
basic_string< charT，traits，Alloc>。然而，我在绝望中只要
我看到了STL来源。我正在使用STLport 5.0-0409和vc 6.0。
如何轻松扩展STL？任何帮助将不胜感激。谢谢。
Hello.
I try to extend STL, for example, add member function like trim_left to
basic_string<charT, traits, Alloc>. However I am in the despair as soon as I see
STL source. I am using STLport 5.0-0409 with vc 6.0.
How can I extend STL easily? Any help will be appreciated. Thanks.
如果你想要一个在std :: string上运行的trim_left函数，那么你需要将它作为一个非b / b来实现会员功能。标准容器
类不是为继承而设计的。没有理由扩展
容器类来添加成员函数，因为与非成员函数方法相比，它没有提供重要的好处。假设你希望从字符串中删除一些字符，你可以这样实现：
//返回结果
std :: string trim_left（const std :: string& s）;
//或
//修改参数
void trim_left（std :: string& s）;
如果你不希望它出现在
全局命名空间。
-
David Hilsee
If you want a trim_left function that operates on a std::string, then you
should implement it as a non-member function. The standard container
classes were not designed for inheritance. There is no reason to extend a
container class to add member functions because that provides no significant
benefits over the non-member function approach. Assuming that you wish to
remove some characters from the string, you could implement it like so:
// returns the result
std::string trim_left( const std::string& s );
// or
// modifies the argument
void trim_left( std::string& s );
You could place this function in a namespace if you don''t want it to be in
the global namespace.
--
David Hilsee
Park Ho-Kyung写道：
Park Ho-Kyung wrote:
你好。
我尝试扩展STL，例如，添加成员函数如trim_left到
basic_string< charT，traits，Alloc> ;。但是，一旦我看到STL来源，我就绝望了。我正在使用STLport 5.0-0409和vc 6.0。
如何轻松扩展STL？任何帮助将不胜感激。谢谢。
Hello.
I try to extend STL, for example, add member function like trim_left to
basic_string<charT, traits, Alloc>. However I am in the despair as soon as I
see
STL source. I am using STLport 5.0-0409 with vc 6.0.
How can I extend STL easily? Any help will be appreciated. Thanks.
从STL中获取自己的类并添加新的
功能。不要搞乱那里的东西，那不是C ++方式！
Ian
Derive your own classes form those in the STL and add your new
functionality. Don''t mess with what''s there, that''s not the C++ way!
Ian
> ;标准容器类不是为继承而设计的。
怎么没有？
> The standard container classes were not designed for inheritance.
How not?
没有理由扩展容器类来添加成员函数
因为与非成员函数方法没有明显的好处。
There is no reason to extend a container class to add member functions
because that provides no significant benefits over the non-member
function approach.
除了语义之外。 IMO，编写
str.trim_left（）而不是trim_left（str）更合乎逻辑。
-
Kevin W :-)
Opera / CSS / webdev blog： http ：//www.exclipy.com/
使用Opera： http://www.opera.com/m2/
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