变量作为数组大小声明符。 [英] Variables as array size declarators.
问题描述
一个包含整数值的变量可以用作整数数组的大小
声明符吗？ g ++没有抱怨，但其他
编译器，如Visual C ++ / 6.0，Borland Builder C ++，Turbo C ++和
Dev-C ++ / 4.0，我测试了它拒绝使用变量大小
声明者。
-
Ayaz Ahmed Khan
你永远在，|网站管理员，
网络空间。 | http://fast-ce.org/
_______________________________________________
我在两年前抛弃了Windows for Linux。
生活从未如此好过。
" Ayaz Ahmed Khan" <再******* @ myrealbox.com>在消息中写道
news：pa ********************************* @ myrealbox。 com ...包含整数值的变量是否可以用作整数数组的大小
声明符？ g ++没有抱怨，但是其他的编译器，例如Visual C ++ / 6.0，Borland Builder C ++，Turbo C ++和Dev-C ++ / 4.0，我在测试它时拒绝使用变量作为大小
声明者。
不确定，但我认为C允许这个，而g ++允许它作为扩展。
但是，它不是标准的一部分C ++。如果你想使用这种
的东西，请使用std :: vector容器类。它会完全符合您想要的价格。
hth
-
jb
（如果你想通过电子邮件回复，用x替换y）
Ayaz Ahmed Khan写道：
< blockquote class =post_quotes>包含整数值的变量是否可以用作整数数组的大小
声明符？
No.
g ++不抱怨，但其他编译器，如Visual C ++ / 6.0，Borland Builder C ++，Turbo C ++和Dev-C ++ / 4.0，我在测试它时拒绝使用变量作为大小声明器。
你可能在ansi中没有使用g ++等模式。尝试至少使用
以下命令行开关：
-ansi -pedantic -W -Wall
Jakob Bieling写道：
Ayaz Ahmed Khan <再******* @ myrealbox.com>在消息中写道
新闻：pa ********************************* @ myrealbox .com ...包含整数值的变量可以用作整数数组的大小
声明符吗？
不确定，但是我认为C允许这样，g ++允许它作为扩展。
但是，它不是标准C ++的一部分。如果你想使用这种东西，请使用std :: vector容器类。它将完全符合您的要求。
这些（可变长度数组）在最新标准中添加到C中。
因为那里实际上很少有编译器实现这个标准，实际上以标准兼容的方式实现这种功能是不稳定的。
Brian Rodenborn
Can a variable containing, say, an integer value be used as size
declarator for an array of integers? g++ does not complain, but other
compilers, such as Visual C++/6.0, Borland Builder C++, Turbo C++, and
Dev-C++/4.0, that I tested it on decline to use variables as size
declarators.
--
Ayaz Ahmed Khan
Yours Forever in, | Webmaster,
Cyberspace. | http://fast-ce.org/
_______________________________________________
I ditched Windows for Linux over two years ago.
Life''s never been better since.
"Ayaz Ahmed Khan" <re*******@myrealbox.com> wrote in message
news:pa*********************************@myrealbox .com...Can a variable containing, say, an integer value be used as size
declarator for an array of integers? g++ does not complain, but other
compilers, such as Visual C++/6.0, Borland Builder C++, Turbo C++, and
Dev-C++/4.0, that I tested it on decline to use variables as size
declarators.
Not sure, but I think C allows this and g++ allows it as an extension.
However, it is not part of Standard C++. If you want to use this kind of
stuff, use the std::vector container class. It will do exactly what you
want.
hth
--
jb
(replace y with x if you want to reply by e-mail)
Ayaz Ahmed Khan wrote:
Can a variable containing, say, an integer value be used as size
declarator for an array of integers?
No.
g++ does not complain, but other compilers, such as Visual C++/6.0,
Borland Builder C++, Turbo C++, and Dev-C++/4.0, that I tested it on
decline to use variables as size declarators.
You probably didn''t use g++ in ansi/iso mode. Try to use at least the
following command line switches:
-ansi -pedantic -W -Wall
Jakob Bieling wrote:
"Ayaz Ahmed Khan" <re*******@myrealbox.com> wrote in message
news:pa*********************************@myrealbox .com...Can a variable containing, say, an integer value be used as size
declarator for an array of integers?
Not sure, but I think C allows this and g++ allows it as an extension.
However, it is not part of Standard C++. If you want to use this kind of
stuff, use the std::vector container class. It will do exactly what you
want.
These (variable-length arrays) were added to C in the latest standard.
As there are few compilers actually implementing that standard yet,
actually having that capability in a standard-compliant way is spotty.
Brian Rodenborn
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