为什么它没有给出任何错误？ [英] why it is not giving any error?
问题描述
大家好，
我已经执行了以下程序，我期待这个程序中的一些错误
但它并没有给出任何错误！ !!!!!!!!!!!!!!!!!!!!!!!
请有人解释一下吗？
#include< stdio。 h>
int main（）
{
char a = 97;
"大家好+ printf（" a =％c\ n的价值，a）;
返回0;
}
提前致谢
Prasanna KP
hi all,
I have executed the following program, I was expecting some errors in
the program but it didn''t give any ERRORS!!!!!!!!!!!!!!!!!!!!!!!!!!!
please can anybody explain me ?
#include<stdio.h>
int main()
{
char a=97;
"hello everyone"+printf("value of a=%c\n",a);
return 0;
}
Thanks in advance
Prasanna K P
推荐答案
prasi写道：
大家好，
我已经执行了以下程序，我期待在程序中出现一些错误，但它并没有给出任何错误!!!!!!!!!!!! !!!!!!!!!!!!!!!
请有人解释一下吗？
＃include< stdio.h>
int main（）
{
char a = 97;
" hello everyone" + printf（" a value of a =％c\ n，a）;
返回0;
}
hi all,
I have executed the following program, I was expecting some errors in
the program but it didn''t give any ERRORS!!!!!!!!!!!!!!!!!!!!!!!!!!!
please can anybody explain me ?
#include<stdio.h>
int main()
{
char a=97;
"hello everyone"+printf("value of a=%c\n",a);
return 0;
}
将一个整数添加到一个字符指针是一个定义明确的操作（它在你的例子中没有副作用。）例如：
char * s =" xyz";
printf（"％c\ n"，*（s + 2））;
将输出''z''。
八月
Adding an integer to a character pointer is a well defined operation (It
has no side effect in your example though.) For instance:
char *s = "xyz";
printf("%c\n", *(s + 2));
will output ''z''.
August
> #include< stdio.h>
> #include<stdio.h>
int main（）
{
char a = 97;
int main()
{
char a=97;
你已将小数值97分配给char变量''a''。这个
infact在C中是合法的，因为字符使用ascii转换。不太确定
为什么，但如果你输入谷歌，ascii代码，你会看到
分配给每个角色的小数。
You have assigned a decimal value of 97 to char variable ''a''. This
infact is legal in C as characters use ascii conversion. Not too sure
about why, but if you type in google, "ascii code" you will see
decimals numbers assigned to each character.
prasi写道：
prasi wrote:
大家好，
我已经执行了以下程序，我在期待程序中的一些错误，但它并没有给出任何错误!!!!!!!!!!!!! !!!!!!!!!!!!!!
请有人解释一下吗？
＃include< stdio.h>
int main（）
{
char a = 97;
" hello everyone" + printf（" a value of a =％c\ n，a）;
返回0;
}
hi all,
I have executed the following program, I was expecting some errors in
the program but it didn''t give any ERRORS!!!!!!!!!!!!!!!!!!!!!!!!!!!
please can anybody explain me ?
#include<stdio.h>
int main()
{
char a=97;
"hello everyone"+printf("value of a=%c\n",a);
return 0;
}
代码没有问题。
它是/傻/，但是那里'编译器没有义务检测
这个愚蠢的代码。
97作为一个字符值合法（不明智，但合法）。 />
将整数添加到指针是合法的 - 如果
它不是 - 那么C将是无用的 - 并且忽略计算值也是合法的并且
经常有用。
你可能会得到一些消息，如果你戳了你的编译器选项
更难。
-
Chris" electric hedgehog" Dollin
我知道三种：热，酷，什么时候开始调整？
There''s nothing wrong with the code.
It''s /stupid/, but there''s no obligation on a compiler to detect
stupid code.
97 is legal as a character value (ill-advised, but legal).
Adding integers to pointers is legal - C would be pretty useless if
it were not - and ignoring calculated values is also legal and
often useful.
You might get some messages if you poked your compiler options a
bit harder.
--
Chris "electric hedgehog" Dollin
"I know three kinds: hot, cool, and what-time-does-the-tune-start?"
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