n00b帮助 [英] n00b help
问题描述
borland c ++ 5.01
字符常量必须是一个或两个字符长
在编译我的第一个c ++程序时可以得到这个任何人都可以有帮助吗？
它突出了这一行作为问题
cout<< 请输入第一个数字：;
这是正确的不是吗？
这里是我用过的代码.. 。
#include< iostream.h>
void main（无效）
{
int iFirst，iSecond，iAnswer;
char cOperator，cCmd;
cout<< endl;
cout<< endl;
cout<< 按任意键启动程序或键入帮助以查看帮助：" ;;
cin>> CCMD; endl;
if（cCmd ==''help''）
cout<< 帮助文件 endl;
cout<< endl;
cout<< 使用这个计算器很简单，下面是
运算符的关键; endl;
cout<< " + = Add \\\
- = Subtract \\\
/ = Divide \\\
* = Multiply";
cout<< endl;
cout<< 请重新启动程序以继续; endl;
else
cout<< 请选择要使用的运营商+/-：" ;;
cin>> cOperator; endl;
cout<< 请输入第一个号码：;
cin>>我先来; endl;
cout<< 请输入第二个数字：;
cin>> iSecond;
if（cOperator ==''+''）
iAnswer = iFirst + iSecond;
否则如果
（cOperator ==''/''）
iAnswer = iFirst / iSecond;
否则如果
（cOperator ==' ' - ''）
iAnswer = iFirst-iSecond;
否则如果
（cOperator ==''*''）
iAnswer = iFirst * iSecond;
else
cout<< endl;
cout<< ****请输入正确的操作员**** endl;
cout<< 你的总和的答案是：" ;;
cout<< iAnswer;
}
i知道它可能不是创建一个简单计算器最简单的方法但
i知道这种方式会起作用但我不知道
i尝试编译时失败的原因是什么？
任何帮助都会非常感激
-
谢谢，
克里斯。
"克里斯托" < CH *** @ juststuff.co.uk>在消息中写道
新闻：2u ************* @ uni-berlin.de ...borland c ++ 5.01
字符常量必须是一个或两个字符长
在编译我的第一个c ++程序时可以有人帮助吗？
它突出显示这一行问题
cout<< 请输入第一个数字：;
这是正确的不是吗？
是的，但还需要许多其他更正。
这里是我用过的代码...
#include< iostream.h>
#include< iostream>
使用命名空间std;
C ++没有调用头文件< iostream.h>，任何告诉你
不同的人都是错的。正确的头文件是< iostream>没有.h。
许多编译器支持< iostream.h>但你不应该使用它b / b
因为它不适合C ++。一些非常古老的编译器没有
< iostream>，它们只有< iostream.h>，如果是这样你那么
你应该得到更好的编译器。有很多免费的编译器
支持现代C ++。
void main（void）
int main（）
main总是返回一个int，再次告诉你不同的人是错的。
{
int iFirst，iSecond，iAnswer;
char cOperator，cCmd;
cout<< endl;
cout<< endl;
cout<< 按任意键启动程序或键入帮助以查看帮助：
" ;; cin>> CCMD; ENDL;
cin>> cCmd;
if（cCmd ==''help''）
好了，这是你的大错。你显然认为cCmd可以是任何数字
的字符。但'char cCmd''表示/ single / character。如果你想要
多个字符，你应该使用字符串和双引号。例如
#include< iostream>
#include< string>
using namespace std;
int main（）
{
cout<< 按任意键启动程序或输入帮助以查看帮助：
" ;;
string cmd;
getline（cin， cmd）;
if（cmd ==" help"）
看起来你忘了在这里放大括号
{
cout<< 帮助文件 endl;
cout<< endl;
cout<< 使用这个计算器很简单，下面是
操作员的关键; endl;
cout<< " + = Add \\\
- = Subtract \\\
/ = Divide \\\
* = Multiply";
cout<< endl;
cout<< 请重新启动程序以继续; ENDL;
这里
}
else
和这里
{
和其他各种地方。
我想你是从过时的源代码中学习C ++，你的代码是老式的b
。获得一本现代C ++教科书是个好主意。
john
Christo写道：borland c ++ 5.01
字符常量必须是一个或两个字符长
Eh？
在编译我的时候得到这个第一个c ++程序可以有人在那里
帮忙吗？
它突出了这一行作为问题
cout<< 请输入第一个数字：;
（错误信息是......？）。事实上这条线本身并不是一个问题 - 很多其他的东西。
提示：
*查找if ... else ...语法，找出大括号。
*查看单引号和双引号之间的区别。
*查看endl的内容是/是，何时/如何使用它。
另外：
*获得一本好的C ++书 - 有很多*东西这个程序有问题
（我相信其他海报会指出你）和编码
风格正在酝酿。
*从一个更简单的程序开始 - Hallo world总是很好:)
问候，
-
Lionel B
Christo写道：
borland c ++ 5.01
字符常量必须是一个或两个字符长
在编译我的第一个c ++程序时得到这个可以帮助那些人吗？
它突出了这一行作为问题
cout<< 请输入第一个号码：;
你确定吗？见下文。
这是正确的不是吗？
是的。
这里是我用过的代码...
#include< iostream.h>
< iostream.h>是一个过时的非标准标题。使用< iostream>相反。
cout，cin和endl将在命名空间std中，所以你需要添加例如：
使用std :: cout;
使用std :: cin;
使用std :: endl;
void main（void）
main必须返回int。 C ++标准不允许任何其他内容。即使
您的编译器可能会接受它，在这种情况下也没有理由违反标准
。
{
int iFirst，iSecond，iAnswer;
char cOperator，cCmd;
请注意，每个cOperator和cCmd只能包含一个字符。
对于cCmd，这还不够，因为它不能保持字符串帮助。所以你要
应该添加#include< string>并使用std :: string;上面，然后将上面一行改为
：
char cOperator;
string cCmd;
cout<< endl;
cout<< endl;
cout<< 按任意键启动程序或键入帮助以查看帮助：
" ;; cin>> CCMD; ENDL;
最后的endl什么都不做。它评估函数指针和
对它没有任何作用。你可能意味着：
cout<<如果（cCmd ==''help''）
你确定这不是问题吗？ ''help''是非法的，因为
字符常量可以容纳一个单个字符，但是你的字符长为4个字符。如果你让cCmd成为如上所述的字符串，你可以写一下：b
$ b if（cCmd ==" help"）
cout<< 帮助文件 endl;
cout<< ENDL;
你错过了一个运营商<<在这两行中的第一行。还要注意
，endl会做两件事。它将\ n写入输出流并刷新
。你不需要冲洗，所以你可以简单地写：
cout<< 帮助文件\ n \ nn;
这样可以节省两次不必要的刷新，而且输入的次数更少。
cout<< 使用这个计算器很简单，下面是
操作员的关键; ENDL;
最后一次是无操作。
cout<< " + = Add \\\
- = Subtract \\\
/ = Divide \\\
* = Multiply";
cout<< endl;
cout<< 请重新启动程序以继续; ENDL;
这里。
其他
cout<< 请选择要使用的运营商+/-：" ;;
cin>> cOperator; ENDL;
又来了。
cout<< 请输入第一个数字：;
cin>>我先来; ENDL;
还有另一个。
顺便说一下，如果用户输入的东西不是什么？该怎么办？
cout< < 请输入第二个数字：;
cin>> iSecond;
if（cOperator ==''+''）
iAnswer = iFirst + iSecond;
如果
（cOperator ==''/''）
iAnswer = iFirst / iSecond;
如果
（cOperator =='' - ''）
iAnswer = iFirst-iSecond;
如果
（cOperator = =''*''）
iAnswer = iFirst * iSecond;
其他
cout<< endl;
cout<< ****请输入正确的操作员**** endl;
cout<< 你的总和的答案是：" ;;
cout<< iAnswer;
}
borland c++ 5.01
character constant must be one or two characters long
get this when compiling my first c++ program can anyone out there help?
it is highlighting this line as the problem
cout << "Please Enter First number: ";
that is correct isnt it though?
here is the code i have used...
#include <iostream.h>
void main (void)
{
int iFirst, iSecond, iAnswer;
char cOperator, cCmd;
cout << endl;
cout << endl;
cout << "Press any key to start the program or type help to view help: ";
cin >> cCmd; endl;
if (cCmd == ''help'')
cout << "Help File" endl;
cout << endl;
cout << "Using this calculator is simple below is the key for the
operators"; endl;
cout << "+ = Add \n - = Subtract \n / = Divide \n * = Multiply";
cout << endl;
cout << "Please restart to program to continue"; endl;
else
cout << "Please select which operator would would like to use +/-: ";
cin >> cOperator; endl;
cout << "Please Enter First number: ";
cin >> iFirst; endl;
cout << "Please Enter Second Number: ";
cin >> iSecond;
if (cOperator == ''+'')
iAnswer = iFirst+iSecond;
else if
(cOperator == ''/'')
iAnswer = iFirst/iSecond;
else if
(cOperator == ''-'')
iAnswer = iFirst-iSecond;
else if
(cOperator == ''*'')
iAnswer = iFirst*iSecond;
else
cout << endl;
cout << "****Please Input A Correct Operator****" endl;
cout << "The Answer To your Sum is: ";
cout << iAnswer;
}
i know it is probably not the easiest way to create a simple calculator but
i know this way will work but i dont know what is casusing the failure when
i try to compile
any help would be much appreciated
--
Thanks,
Chris.
"Christo" <ch***@juststuff.co.uk> wrote in message
news:2u*************@uni-berlin.de...borland c++ 5.01
character constant must be one or two characters long
get this when compiling my first c++ program can anyone out there help?
it is highlighting this line as the problem
cout << "Please Enter First number: ";
that is correct isnt it though?
Yes, but many other corrections needed.
here is the code i have used...
#include <iostream.h>
#include <iostream>
using namespace std;
C++ does not have a header file called <iostream.h>, any one who tells you
different is wrong. The cirrect header file is <iostream> without the .h.
Many compilers however support <iostream.h> but you should not use it
because it isn''t proper C++. A few very old compilers do not have
<iostream>, they only have <iostream.h>, if that is the case for you then
you should get a better compiler. There are plently of free compilers
available which support modern C++.
void main (void)
int main()
main always returns an int, again anyone whoe tells you different is wrong.
{
int iFirst, iSecond, iAnswer;
char cOperator, cCmd;
cout << endl;
cout << endl;
cout << "Press any key to start the program or type help to view help: "; cin >> cCmd; endl;
cin >> cCmd;
if (cCmd == ''help'')
OK here''s your big mistake. You obviously think that cCmd can be any number
of characters. But ''char cCmd'' means a /single/ character. If you want
multiple characters you should use strings and double quotes. For instance
#include <iostream>
#include <string>
using namespace std;
int main()
{
cout << "Press any key to start the program or type help to view help:
";
string cmd;
getline(cin, cmd);
if (cmd == "help")
Looks like you''ve forgotten to put curly brackets here
{
cout << "Help File" endl;
cout << endl;
cout << "Using this calculator is simple below is the key for the
operators"; endl;
cout << "+ = Add \n - = Subtract \n / = Divide \n * = Multiply";
cout << endl;
cout << "Please restart to program to continue"; endl;
And here
}
else
And here
{
and various other places.
I think you are learning C++ from an out of date source, your code is
old-fashioned. It would be a good idea to get a modern C++ text book.
john
Christo wrote:borland c++ 5.01
character constant must be one or two characters long
Eh?
get this when compiling my first c++ program can anyone out there help?
it is highlighting this line as the problem
cout << "Please Enter First number: ";
(and the error message is...?). In fact this line is not in itself a
problem - many other things are.
Hints:
* Look up the if .. else ... syntax and find out about curly brackets.
* Look up the difference between single and double quotes.
* Look up what "endl" is/does and when/how to use it.
Also:
* Get a good C++ book - there are *many* things wrong with this program
(which I''m sure other posters will point out to you) and the coding
style is apalling.
* Start with a simpler program - "Hallo world" is always good :)
Regards,
--
Lionel B
Christo wrote:
borland c++ 5.01
character constant must be one or two characters long
get this when compiling my first c++ program can anyone out there help?
it is highlighting this line as the problem
cout << "Please Enter First number: ";
Are you sure about that? See below.
that is correct isnt it though?
Yes.
here is the code i have used...
#include <iostream.h>
<iostream.h> is an outdated non-standard header. Use <iostream> instead.
cout, cin and endl will then be in namespace std, so you need to add e.g.:
using std::cout;
using std::cin;
using std::endl;
void main (void)
main must return int. Nothing else is allowed by the C++ standard. Even if
your compiler might accept it, there is no reason to violate the standard
in this case.
{
int iFirst, iSecond, iAnswer;
char cOperator, cCmd;
Note that each of cOperator and cCmd can hold exactly one single character.
For cCmd, that is not enough, since it can''t hold the string "help". So you
should add #include <string> and using std::string; above, and then change
the above line into:
char cOperator;
string cCmd;
cout << endl;
cout << endl;
cout << "Press any key to start the program or type help to view help:
"; cin >> cCmd; endl;
The endl at the end doesn''t do anything. It evaluates a function pointer and
does nothing with it. You probably meant:
cout << endl;
if (cCmd == ''help'')
Are you sure that this wasn''t the line in question? ''help'' is illegal, since
character constants can hold one single character, but yours is 4
characters long. If you make cCmd a string as mentioned above, you can
write:
if (cCmd == "help")
cout << "Help File" endl;
cout << endl;
You''re missing an operator << in the first of those two lines. Note also
that endl does two things. It writes a \n to the output stream and flushes
it. You don''t need the flush here, so you could simply write:
cout << "Help File\n\n";
This saves you two unnecessary flushes and is less to type.
cout << "Using this calculator is simple below is the key for the
operators"; endl;
Again a no-op at the end.
cout << "+ = Add \n - = Subtract \n / = Divide \n * = Multiply";
cout << endl;
cout << "Please restart to program to continue"; endl;
And here.
else
cout << "Please select which operator would would like to use +/-: ";
cin >> cOperator; endl;
And here again.
cout << "Please Enter First number: ";
cin >> iFirst; endl;
And another one.
Btw, what if the user enters something that isn''t a nuber?
cout << "Please Enter Second Number: ";
cin >> iSecond;
if (cOperator == ''+'')
iAnswer = iFirst+iSecond;
else if
(cOperator == ''/'')
iAnswer = iFirst/iSecond;
else if
(cOperator == ''-'')
iAnswer = iFirst-iSecond;
else if
(cOperator == ''*'')
iAnswer = iFirst*iSecond;
else
cout << endl;
cout << "****Please Input A Correct Operator****" endl;
cout << "The Answer To your Sum is: ";
cout << iAnswer;
}
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