C中的空格 [英] Spaces in C

问题描述

我这里有一小块程序


基本上它的作用是，它复制可变宽度的字符串。

基础是直到它找到逗号，。输入是一个CSV /逗号分隔

文件。


现在的问题是它没有计算Spaces。例如，阅读下面的

以下程序是可以的：


123，你好，3422C

3994，Hii ，39948D


结果：很好，有效;


但如果我有如下字符串的话;

123，你好，你好，99399 C


结果：嗨之后无法阅读因为空间，你能否建议将任何

代码更改为以下存根？


谢谢

J

--------------------------

int j = 0;

char c;

c = ptr [0];

ibic [0] = c;

while（c！=''，'' ）

{

++ j;

c = ptr [j];

ibic [j] = c ;

}

ibic [j] =''\ 0'';

返回0;

-------------------------

Hi,

I have a little piece of program here

Basically what it does is, it copies the strings of variable widths. The
basis is until it finds a comma ",". The input is a CSV/Comma Separated
file.

Now the problem is that it is not counting Spaces. For example to read the
following line with the below Program is OK:

123, Hello, 3422C
3994,Hii,39948D

Result: Fine, works;

But if I have the strings like the below;
123, Hi How are you,99399 C

Result: Fails to read after "Hi" because of the space, can you suggest any
code changes to below stub?

Thanks
J
--------------------------
int j = 0;
char c;
c = ptr[0];
ibic[0] = c;
while(c != '','')
{
++j;
c = ptr[j];
ibic[j] = c;
}
ibic[j] = ''\0'';
return 0;
-------------------------

推荐答案

Joriveek <无**** @ please.com>在消息中写道

news：ds ********** @ reader01.news.esat.net ...

"Joriveek" <no****@please.com> wrote in message
news:ds**********@reader01.news.esat.net...

<我这里有一小段程序

基本上它是做什么的，它复制了可变宽度的字符串。
基础是直到它找到逗号，。输入是一个CSV /逗号分隔的文件。

现在的问题是它没有计算Spaces。例如用以下内容阅读
以下程序是可以的：

123，你好，3422C
3994，Hii，39948D

结果：很好，有效;

但如果我有如下的字符串;
123，你好，你好，99399 C

结果：无法阅读后 ;您好"因为空间，你能否建议将任何代码更改到下面的存根？

谢谢
J
------------- -------------
int j = 0;
char c;
c = ptr [0];
ibic [0] = c ;
while（c！=''，''）
{
++ j;
c = ptr [j];
ibic [j] = c ;
}
ibic [j] =''\ 0'';
返回0;
---------------- ---------

Hi,

I have a little piece of program here

Basically what it does is, it copies the strings of variable widths. The
basis is until it finds a comma ",". The input is a CSV/Comma Separated
file.

Now the problem is that it is not counting Spaces. For example to read the
following line with the below Program is OK:

123, Hello, 3422C
3994,Hii,39948D

Result: Fine, works;

But if I have the strings like the below;
123, Hi How are you,99399 C

Result: Fails to read after "Hi" because of the space, can you suggest any
code changes to below stub?

Thanks
J
--------------------------
int j = 0;
char c;
c = ptr[0];
ibic[0] = c;
while(c != '','')
{
++j;
c = ptr[j];
ibic[j] = c;
}
ibic[j] = ''\0'';
return 0;
-------------------------

你确定问题出在那个存根中，而不是在例程中读取

和填写''ptr''？

Rod Pemberton

Are you sure the problem is in that stub and not in the routine that reads
and fills ''ptr''?

Rod Pemberton

Joriveek写道在02/13/06 11:00，：

Joriveek wrote On 02/13/06 11:00,:

我这里有一小段程序

Hi,

I have a little piece of program here

请将整个内容发布 - 如果它很长，请将其减少到

必需品，但是发布一个完整的可编辑的
程序。当你生病时，你是否将整个

的身体带到医生处或只是送一绺头发？


-
< a href =mailto：Er ********* @ sun.com> Er ********* @ sun.com

Please post the entire thing -- reduce it to its
essentials if it''s long, but post a complete compilable
program. When you are sick, do you take your entire
body to the doctor or just send a lock of your hair?

--
Er*********@sun.com

抱歉，这是用于读取CSV文件;

如果有空格，它不起作用，只读它是否是连续的

string。

" Rod Pemberton" <做********* @ sorry.bitbucket.cmm>在消息中写道

news：43 ******** @ news.bea.com ...

sorry, it is for reading a CSV file;
if there are spaces, it is not working, just reading if it is a continuous
string.
"Rod Pemberton" <do*********@sorry.bitbucket.cmm> wrote in message
news:43********@news.bea.com...

Joriveek <无**** @ please.com>在消息中写道
新闻：ds ********** @ reader01.news.esat.net ...

"Joriveek" <no****@please.com> wrote in message
news:ds**********@reader01.news.esat.net...

我这里有一小块程序

基本上它做的是，它复制可变宽度的字符串。
基础是直到它找到逗号，。输入是一个CSV /逗号分隔的文件。

现在的问题是它没有计算Spaces。例如阅读

下面的程序如下程序可以：

123，你好，3422C
3994，Hii，39948D

但如果我有下面的字符串;
123，你好，你好，99399 C

结果：失败在嗨之后阅读因为空间，你能否建议将任何代码更改到下面的存根？

谢谢
J
--------- -----------------
int j = 0;
char c;
c = ptr [0];
ibic [ 0] = c;
while（c！=''，''）
{
++ j;
c = ptr [j];
ibic [ j] = c;
}
ibic [j] =''\ 0'';
返回0;
------------ -------------

Hi,

I have a little piece of program here

Basically what it does is, it copies the strings of variable widths. The
basis is until it finds a comma ",". The input is a CSV/Comma Separated
file.

Now the problem is that it is not counting Spaces. For example to read
the
following line with the below Program is OK:

123, Hello, 3422C
3994,Hii,39948D

Result: Fine, works;

But if I have the strings like the below;
123, Hi How are you,99399 C

Result: Fails to read after "Hi" because of the space, can you suggest
any
code changes to below stub?

Thanks
J
--------------------------
int j = 0;
char c;
c = ptr[0];
ibic[0] = c;
while(c != '','')
{
++j;
c = ptr[j];
ibic[j] = c;
}
ibic[j] = ''\0'';
return 0;
-------------------------

你确定问题出在那个存根中，而不是在例程中读取和填充''ptr ''？

Rod Pemberton

Are you sure the problem is in that stub and not in the routine that reads
and fills ''ptr''?

Rod Pemberton

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