反正比较INT要绘制的?ANDROID [英] Anyway to compare int to drawable?ANDROID
问题描述
反正是有比较s到一个?在这种code我的int作为答案,如果绘制==小号
然后我要显示一个正确!
敬酒消息。任何帮助将是AP preciated。
btn1.setOnClickListener(新OnClickListener()
{
@覆盖
公共无效的onClick(视图v)
{
int类型= R.drawable.exitbtn;
资源RES = getResources();
可绘制绘制= res.getDrawable(R.drawable.exitbtn);
对象A =绘制;
若(a == S)
{
ImageView的ImageView的=(ImageView的)findViewById(R.id.imageView1);
Toast.makeText(getApplicationContext(),正确!,Toast.LENGTH_SHORT).show();
imageview.setImageDrawable(绘制);
btn1.setText(1);
btn2.setText(2);
btn3.setText(3);
btn4.setText(4);
}
}
}
在绘制对象
实例相比于 INT
没有任何意义。什么是你想怎么办?是否要检查方法 res.getDrawable(R.drawable.exitbtn);
返回正确的对象
我认为这是多余的获取从R-文件标识符:
int类型= R.drawable.exitbtn;
然后使用同样的标识获取该对象:
可绘制绘制= res.getDrawable(R.drawable.exitbtn);
,然后尝试检查它是否是真正合适的对象通过比较IDS。
我认为有对错误没有地方(特别是,一个int值的混乱),当它涉及到由ID获取一个绘制对象。如果你想确保对象被创建,检查对空。
可绘制绘制= res.getDrawable(R.drawable.exitbtn);
如果(绘制!= NULL){
//做的东西
} 其他 {
//处理情况没有绘制
}
另外,我觉得没有办法从可绘制对象获取的ID。通过 getDrawable
返回的实例并不包含这些信息。
更重要的是,你可以使用一个事实,即 getDrawable
可以抛出一个 NotFoundException
如果ID是有点不对。检查文档了解详细信息。
Is there anyway to compare s to a? In this code I have int s as the answer and if the drawable == s
then I want to display a "Correct!"
toast message. Any help would be appreciated.
btn1.setOnClickListener(new OnClickListener()
{
@Override
public void onClick(View v)
{
int s = R.drawable.exitbtn;
Resources res = getResources();
Drawable drawable = res.getDrawable(R.drawable.exitbtn);
Object a=drawable;
if(a==s)
{
ImageView imageview =(ImageView)findViewById(R.id.imageView1);
Toast.makeText(getApplicationContext(), "CORRECT!", Toast.LENGTH_SHORT).show();
imageview.setImageDrawable(drawable);
btn1.setText("1");
btn2.setText("2");
btn3.setText("3");
btn4.setText("4");
}
}
}
Comparing a Drawable
instance to an int
doesn't make sense. What are you trying to do? Do you want to check if the method res.getDrawable(R.drawable.exitbtn);
returns the right object?
I think it's redundant to fetch an identifier from R-file:
int s = R.drawable.exitbtn;
Then fetch the object using the very same identifier:
Drawable drawable = res.getDrawable(R.drawable.exitbtn);
And then try to check whether it's really the right object by comparing ids.
I think that there's no place for mistake (specifically, confusion of an int value) when it comes to getting a Drawable by id. If you want to be sure the object has been created, check it against a null.
Drawable drawable = res.getDrawable(R.drawable.exitbtn);
if(drawable != null){
//do stuff
} else {
//handle the situation where there's no drawable
}
Also, I think there's no way to fetch an id from a Drawable object. The instance returned by getDrawable
does not contain such information.
Better yet, you can use the fact that getDrawable
can throw a NotFoundException
if the id is somehow wrong. Check the docs for details.
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