谷歌地图API街坐标 [英] Google Maps API Street Coordinates

问题描述

我想提出一个Android应用程序。是否有可能来检查，如果用户（给予一定的坐标）正面临着街道，如果这条街是在10-20ft了？

I am making an android app. Is it possible to check if a user (given some coordinates) is facing a street and if that street is within 10-20ft away?

如果不是，是否有一个开放源码的地图，我可以花纹，通过手动使用code /协调，看是否有附近的街头？我想打一个导航系统，为盲人，我需要一些方法来检查用户是否站在马路中间。

If not, is there an open source map which I can "tread" through manually using code/coordinates to see if there is a nearby "street"? I want to make a navigation system for the blind and I need some way to check if the user is standing on the middle of the street.

谢谢， 罗希特

推荐答案

您需要阅读上的谷歌地图API地理编码：

You'll want to read up on the Google Maps Geocoding API:

HTTP：//$c$c.google.com/apis /地图/文档/地理编码/

如果你在Android上，有一个特殊的 地理codeR 类，将调用谷歌地图为您提供：

If you're on Android, there's a special Geocoder class that will call Google Maps for you:

Geocoder geocoder = new Geocoder(this, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(lat, lng, 1);

（来源：机器人：反向地理编码 - getFromLocation ）

美中不足的是，这只是去给最有可能的地址为用户的当前位置 - 你没有得到指定模糊因数或类似​​的东西。即便如此，10-20英尺。应该是足够接近此相匹配。

The catch is that this just going to give the most likely address for the user's current location -- you don't get to specify a fuzz factor or anything like that. Even then, 10-20 ft. should be close enough for this to match.

如果这不会得到你所需要的数据，你可能也想看看 OpenStreetMap的，这是一个开放的地图数据库。我没有太多的经验与它自己，但有文档浏览： http://wiki.openstreetmap.org /维基/ Main_Page

If this doesn't get you the data you need, you might also want to look at OpenStreetMap, which is an open maps database. I don't have much experience with it myself, but there's documentation here: http://wiki.openstreetmap.org/wiki/Main_Page

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