有人可以帮我解释这个宏吗? [英] Could anybody explain this macro for me?

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问题描述

#define D(y ...)(const int []){y}


我的理解是D正在接受各种长度参数y

这是一个const int数组。我是对的吗?


谢谢。

#define D(y...) (const int []) {y}

My understand is that D is taking in a various length parameter y
which is an array of const int. Am I right?

Thanks.

推荐答案

11月13日,12:46 * pm," ; webinfin ... @ gmail.com" < webinfin ... @ gmail.com>

写道:
On Nov 13, 12:46*pm, "webinfin...@gmail.com" <webinfin...@gmail.com>
wrote:

#define D(y ...)(const int [ ]){y}


我的理解是D正在接受各种长度参数y

这是一个const int数组。我对吗?
#define D(y...) (const int []) {y}

My understand is that D is taking in a various length parameter y
which is an array of const int. Am I right?



这是语法错误。你确定你正确地转录了

吗?

This is a syntax error. Are you sure you transcribed
it correctly?


Old Wolf写道:
Old Wolf wrote:

11月13日下午12:46,webinfin ... @ gmail.com < webinfin ... @ gmail.com>

写道:
On Nov 13, 12:46 pm, "webinfin...@gmail.com" <webinfin...@gmail.com>
wrote:

> #define D(y ...)(const int []){y}

我的理解是D正在接受各种长度参数y
这是一个const int数组。我对吗?
>#define D(y...) (const int []) {y}

My understand is that D is taking in a various length parameter y
which is an array of const int. Am I right?



这是语法错误。你确定你正确地转录了

吗?


This is a syntax error. Are you sure you transcribed
it correctly?



对我而言,它看起来像是新C标准的可变宏,而不是C ++标准中的

To me it looks like a variadic macro from the newer C standard, not
yet in the C++ standard.


我们********* @ gmail.com 写道:

#define D(y ...)(const int []){y}


我的理解的是D是一个各种长度参数y

这是一个const int数组。我是对的吗?
#define D(y...) (const int []) {y}

My understand is that D is taking in a various length parameter y
which is an array of const int. Am I right?



尝试clc,这看起来像C99。


-

伊恩柯林斯

Try c.l.c, this looks like C99.

--
Ian Collins


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