CString不会去cout [英] CString will not go to cout

问题描述

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推荐答案

因为printf（和类似函数）中的％s表示堆栈上的参数指向到ac字符串，这是一个零终止的字符数组。您的变量st是CString类型的对象，而不是指向c字符串的指针。但是你可以将它转换成一个指向交流字符串的常量指针


（LPCSTR）st / /

因为CString对象为此实现了一个运算符所以


printf_s（"％s \ n"，（LPCSTR）st）;


应该适合你。

Because %s in printf (and similar functions) indicates a parameter on the stack that points to a c string, that is a zero terminated array of characters. Your variable, st is an object of type CString not a pointer to a c string. You can however cast it to a constant pointer to a c string

(LPCSTR)st

because the CString object implements an operator for this so

printf_s("%s\n",(LPCSTR)st);

should work for you.

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对不起，另一件事是CString处理Windows正在使用的字符类型。这通常是unicode。


printf（及相关函数）但是仍然使用直的ASCII字符串。


要打印一个CString，你需要将字符从Unicode转换为ASCII。


应该通过google或msdn提供大量有关此内容的信息。

Sorry the other thing is that CString deals with what ever character type Windows is using. This is normally unicode.

printf (and related functions) however still use a straight ASCII string.

To printf a CString you will need to convert the characters from Unicode to ASCII.

There should be plenty of information about this available either through google or msdn.

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