setState用于嵌套对象 [英] setState for nested objects

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本文介绍了setState用于嵌套对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个嵌套对象作为状态,我在组件中有一个表单。每当用户在表单中输入内容时,我就会考虑更新状态,并避免为每个输入创建许多函数,而我正在考虑使用switch创建单个函数。

I have a nested object as a state and I have a form in a component. I was thinking of updating the state every time the user enter something in the form and to avoid creating many functions for each input I was thinking of creating a single function using switch.


  1. 使用switch创建单个函数是个好主意吗?

  2. 如何更新对象的单个嵌套元素?

我尝试使用以下代码但不起作用:

I have tried with the following code but it doesn't work:

class App extends Component {
  constructor(props) {
      super(props)
      this.state = {
        minutes: null,
        interests: {
          business: false,
          code: false,
          design: false
        },
        errors: []
      }
  }

  updatePreferences = (preferenceName, enteredValue) => {
    switch (preferenceName) {
      case preferenceName === "minutes":
        this.setState({minutes: enteredValue})
        return
      case preferenceName === "business":
        this.setState({interests.business: !this.state.interests.business})
        return
      case default:
        return
    }

  }
}


推荐答案

当然你可以使用开关,没有错误的AFAIK。

Of course you can use switch, Nothing wrong AFAIK.

并用<$更新嵌套对象C $ C>的setState 。参见示例

  updatePreferences = (preferenceName, enteredValue) => {
     switch (preferenceName) {
      case preferenceName === "minutes":
        this.setState({minutes: enteredValue});
        return
      case preferenceName === "business":
        this.setState({...this.state, interests: {
          ...this.state.interests,
          business: !this.state.interests.business
        }});
        return
      default:
        return
    }

  }

这篇关于setState用于嵌套对象的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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