JavaScript / jQuery从节点的text（）值中删除字符160 - Regex [英] JavaScript/jQuery removing character 160 from a node's text() value - Regex

问题描述

$('#customerAddress').text().replace(/\xA0/,"").replace(/\s+/," ");

追踪范围中的值（id = customerAddress），我想减少所有部分空格到单个空格。 / \s + /可以工作，除了这个应用程序在街道地址和州/邮编之间获得160个字符
有什么更好的方式来写这个？这目前无效。

Going after the value in a span (id=customerAddress) and I'd like to reduce all sections of whitespace to a single whitespace. The /\s+/ whould work except this app gets some character 160's between street address and state/zip What is a better way to write this? this does not currently work.

更新：
我已经发现

UPDATE: I have figured out that

$('.customerAddress').text().replace(/\s+/g," ");

清除160s和空格。
但是我怎么写一个正则表达式只是在160年代之后？

clears the 160s and the spaces. But how would I write a regex to just go after the 160s?

$('.customerAddress').text().replace(String.fromCharCode(160)," ");

甚至没有工作。

注意：我正在使用Firefox / Firebug进行测试

Note: I'm testing in Firefox / Firebug

推荐答案

\s 已包含字符U + 00A0 ：

\s does already contain the character U+00A0:

[\t\n\v\f\r \u00a0\u2000\u2001\u2002\u2003\u2004\u2005\u2006\u2007\u2008\u2009\u200a\u200b\u2028\u2029\u3000]

但你应该添加 g 修饰符来全局替换：

But you should add the g modifier to replace globally:

$('#customerAddress').text().replace(/\s+/g, " ")

否则只会替换第一场比赛。

Otherwise only the first match will be replaced.

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