Javascript findIndex不是一个函数 [英] Javascript findIndex is not a function

问题描述

我有一个json数组：

  [
 {id：19，name： Jed，姓氏：DIAZ，爱好：照片，生日：2011/11/22}，
 {id：20，name：Judith ，姓：HENDERSON，爱好：宠物，生日：1974/06/12}，
 {id：21，name：Nicolai，姓氏：GRAHAM，业余爱好：阅读，生日：2005/01/22}，
 {id：22，name：Vasile，lastname ：BRYANT，业余爱好：唱歌，生日：1987/03/17} 
] 
  

从json数组中删除项目的函数

  removeItem：function（removeId）{
 //参数验证
返回dataLoad.then（函数（数据）{
 
f = data.findIndex（function（item）{return item.id == removeId;}）; 
 
如果（f <0）
返回false; 
 data.splice（f，1）; 
 
 LS.setData（数据，cutomers ）; 
 
返回true; 
}）; 
} 
  

当代码运行时出现错误：

findIndex不是函数

错误行

  f = data.findIndex（function（item）{return item.id == removeId;}）; 
  

解决方案

findIndex 不是

I have a json array:

[    
  {"id":19,"name":"Jed", "lastname":"DIAZ", "hobby":"photo", "birthday":"2011/11/22"},
  {"id":20,"name":"Judith", "lastname":"HENDERSON", "hobby":"pets", "birthday":"1974/06/12"},
  {"id":21,"name":"Nicolai", "lastname":"GRAHAM", "hobby":"reading", "birthday":"2005/01/22"},
  {"id":22,"name":"Vasile", "lastname":"BRYANT", "hobby":"singing", "birthday":"1987/03/17"}
]

function to remove a item from json array

 removeItem: function(removeId){
   //paramater validation
   return dataLoad.then(function(data){

     f = data.findIndex(function(item) { return item.id == removeId; });

     if(f < 0)
       return false;
     data.splice(f,1);

     LS.setData(data,"cutomers");

     return true;
   });
 }

When the code is running there is an error:

findIndex is not a function

error line

 f = data.findIndex(function(item) { return item.id == removeId; });

解决方案

findIndex is not a prototype method of Array in ECMASCRIPT 262, you might need filter combined with indexOf, instead, it has the advantage of stopping searching as soon as entry is found

var f;
var filteredElements = data.filter(function(item, index) { f = index; return item.id == removeId; });


if (!filteredElements.length) {
    return false;
}

data.splice(f, 1);

---

EDIT as suggested in comments by Nina Scholz:

This solution is using Array.prototype.some instead

var f;
var found = data.some(function(item, index) { f = index; return item.id == removeId; });

if (!found) {
    return false;
}

data.splice(f, 1);

---

Found at Array.prototype.findIndex MDN

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