Ksoap2在Android中不能序列 [英] Ksoap2 in android cannot serialize

问题描述

我用ksoap2在机器人

发送号码列表作为字符串

但有错误：

java.lang.RuntimeException的不能序列

我寻找一个解决这个错误，但结果没有改变

可以帮我请

 公共字符串发送（ArrayList中＆LT;字符串＆GT; contactlist）
{
    尝试{
SoapObject请求=新SoapObject（WSDL_TARGET_NAMESPACE，OPERATION_NAME）;
的PropertyInfo PI =新的PropertyInfo（）;
            pi.setType（为String.class）;
            pi.setName（contactlist）;
            pi.setValue（contactlist）;
            request.addProperty（contactlist，PI）;
。StrictMode.ThreadPolicy政策=新StrictMode.ThreadPolicy.Builder（）permitAll（）建（）;
        StrictMode.setThreadPolicy（政策）;

        //创建SOAP信封
        SoapSerializationEnvelope包=新SoapSerializationEnvelope（SoapEnvelope.VER11）;
        新MarshalBase64（）寄存器（信封）; //此行是为序列化

        //可以评论说，行了，如果您的Web服务是不是.NET之一。
        envelope.dotNet = TRUE;

        envelope.setOutputSoapObject（要求）;
        AndroidHttpTransport androidHttpTransport =新AndroidHttpTransport（http://10.0.2.2:54869/Service1.asmx）;
        androidHttpTransport.debug = TRUE;
}
    赶上（例外的例外）
        {
            返回exception.toString（）;
        }
    尝试
        {
            androidHttpTransport.call（SOAP_ACTION，包）;
            //字符串结果= envelope.getResponse（）的toString（）;
            返回; //结果;
        }
    赶上（例外的例外）
        {
            返回exception.toString（）;
        }
 

解决方案

使用这个类序列化

 公共类MarshalDouble实现元帅{
        公共对象readInstance（XmlPullParser分析器，字符串命名空间，
                字符串名称，预期的PropertyInfo）抛出IOException异常，
                XmlPullParserException {

            返回Double.parseDouble（parser.nextText（））;
        }

        公共无效寄存器（SoapSerializationEnvelope厘米）{
            cm.addMapping（cm.xsd，双，Double.class，这一点）;

        }

        公共无效writeInstance（XmlSerializer的作家，对象OBJ）
                抛出IOException异常{
            writer.text（obj.toString（））;
        }
    }
 

添加此行包围

  envelope.dotNet = TRUE;
    envelope.implicitTypes = TRUE;
    envelope.encodingStyle = SoapSerializationEnvelope.XSD;
    MarshalDouble MD =新MarshalDouble（）;
    md.register（信封）;
 

I use ksoap2 in android

to send list of numbers as string

But it have error:

java.lang.runtimeexception cannot serialize

I search a solution to this error but result not change

Can Help me please

public String Send(ArrayList<String> contactlist)
{
    try{
SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME);
PropertyInfo pi=new PropertyInfo();
            pi.setType(String.class);
            pi.setName("contactlist");
            pi.setValue(contactlist);
            request.addProperty("contactlist", pi);
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
        StrictMode.setThreadPolicy(policy); 

        // Creating SOAP envelope           
        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
        new MarshalBase64().register(envelope); // this line is for serialization

        //You can comment that line if your web service is not .NET one.
        envelope.dotNet = true;

        envelope.setOutputSoapObject(request);
        AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport("http://10.0.2.2:54869/Service1.asmx");
        androidHttpTransport.debug = true;
}
    catch (Exception exception)
        {
            return exception.toString();
        }
    try
        {
            androidHttpTransport.call(SOAP_ACTION, envelope);
            //String result = envelope.getResponse().toString();
            return "";//result;
        }
    catch (Exception exception)
        {
            return exception.toString();
        }

解决方案

Use this class for Serialization

public class MarshalDouble implements Marshal {
        public Object readInstance(XmlPullParser parser, String namespace,
                String name, PropertyInfo expected) throws IOException,
                XmlPullParserException {

            return Double.parseDouble(parser.nextText());
        }

        public void register(SoapSerializationEnvelope cm) {
            cm.addMapping(cm.xsd, "double", Double.class, this);

        }

        public void writeInstance(XmlSerializer writer, Object obj)
                throws IOException {
            writer.text(obj.toString());
        }
    }

Add this line to envelop

    envelope.dotNet = true;
    envelope.implicitTypes = true;
    envelope.encodingStyle = SoapSerializationEnvelope.XSD;
    MarshalDouble md = new MarshalDouble();
    md.register(envelope);

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