如果填料测试范围基本 [英] basic if stuff- testing ranges
问题描述
Sheesh，我一直在努力寻找如何做这个简短的手：
如果0 x< 20：打印在...内
因此x必须为0且< 20.
我通常会这样做：
如果x 0和x< 20：打印内
规则是什么？它甚至存在吗？
我最近在列表上读到了类似的内容但是找不到它，那就是我想要尝试它的冲动从。我在文档中找不到任何东西，但是再次（imho）Python文档就像一个纠结的丛林......
\ d
Sheesh, I''ve been going spare trying to find how to do this short-hand:
if 0 x < 20: print "within"
So that x must be 0 and < 20.
I usually do:
if x 0 and x < 20: print "within"
What''s the rule? Does it even exist?
I read something like it recently on the list but can''t find it, that''s
where I got the urge to try it from. I can''t find anything in the docs, but
then again (imho) the Python docs are like a tangled jungle...
\d
推荐答案
Donn Ingle写道：
Donn Ingle wrote:
Sheesh，我去过备用试图找到如何做这个简短的手：
如果0 x< 20：打印在...内
因此x必须为0且< 20.
我通常会这样做：
如果x 0和x< 20：打印内
规则是什么？它甚至存在吗？
Sheesh, I''ve been going spare trying to find how to do this short-hand:
if 0 x < 20: print "within"
So that x must be 0 and < 20.
I usually do:
if x 0 and x < 20: print "within"
What''s the rule? Does it even exist?
如果0< x< 20：
？
Mel。
if 0 < x < 20:
?
Mel.
Donn Ingleaécrit：
Donn Ingle a écrit :
Sheesh，我一直在努力寻找如何做这个简短的手：
如果0 x< 20：打印在...内
Sheesh, I''ve been going spare trying to find how to do this short-hand:
if 0 x < 20: print "within"
你的意思是：0< x< 20？
$ x $ bx in xrange（1,20）？
you mean : 0 < x < 20 ?
or
x in xrange(1,20) ?
>
因此x必须为0且< 20.
我通常会这样做：
如果x 0和x< 20：打印内
规则是什么？它甚至存在吗？
>
So that x must be 0 and < 20.
I usually do:
if x 0 and x < 20: print "within"
What''s the rule? Does it even exist?
难以在repl上检查它吗？
is that hard to check it at the repl ?
我最近读了类似的东西列表但是找不到它，那是'b
我从中得到了尝试它的冲动。我在文档中找不到任何东西，但
然后再次（imho）Python文档就像一个纠结的丛林......
I read something like it recently on the list but can''t find it, that''s
where I got the urge to try it from. I can''t find anything in the docs, but
then again (imho) the Python docs are like a tangled jungle...
< what smug，refrained />
<something smug, refrained/>
>
\ n
>
\d
11月26日上午5:49，Donn Ingle< donn.in ... @ gmail.comwrote：
On Nov 26, 5:49 am, Donn Ingle <donn.in...@gmail.comwrote:
Sheesh，我一直在努力寻找如何做这个简短的手：
如果0 x< 20：打印在...内
Sheesh, I''ve been going spare trying to find how to do this short-hand:
if 0 x < 20: print "within"
这意味着如果x小于0且x <0 20"
That means "if x LESS THAN 0 and x < 20".
>
因此x必须为0且< 20.
>
So that x must be 0 and < 20.
因此，如果0< b< b>那么请尝试
x< 20：
So try
if 0 < x < 20:
>
我通常这样做：
如果x 0和x< 20：打印内
规则是什么？它甚至存在吗？
我最近在列表上读到了类似的内容但是找不到它，那就是我想要尝试它的冲动从。我在文档中找不到任何东西，但
然后再次（imho）Python文档就像一个纠结的丛林......
>
I usually do:
if x 0 and x < 20: print "within"
What''s the rule? Does it even exist?
I read something like it recently on the list but can''t find it, that''s
where I got the urge to try it from. I can''t find anything in the docs, but
then again (imho) the Python docs are like a tangled jungle...
可能的手册：教程&参考
教程：检查内容，if statement和看起来可能，但没有运气
参考：检查内容，比较看起来很可能，并且
http://docs.python.org/ ref / comparisons.html 说：
"""
比较可以任意链接，例如x< y< = z相当于
到x< y和y< = z，除了y仅被评估一次（但是在两个
的情况下，当x< y被发现为假时，z根本不被评估）。
"""
Likely manuals: Tutorial & Reference
Tutorial: check contents, "if statement" looks possible, but no luck
Reference: check contents, "comparisons" looks possible, and
http://docs.python.org/ref/comparisons.html says:
"""
Comparisons can be chained arbitrarily, e.g., x < y <= z is equivalent
to x < y and y <= z, except that y is evaluated only once (but in both
cases z is not evaluated at all when x < y is found to be false).
"""
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