从列表创建唯一组合 [英] Creating unique combinations from lists

问题描述

我有三个清单...例如


a = [''big''，''small''，''medium''];

b = [''old''，''new''];

c = [''blue''，''green''];


我想拿这些并最终得到他们所有的组合

创建如下列表

[''big''，''old'' ，''blue'']

[''小''，''旧''，''蓝'''

[''medium''，' 'old''，''blue'']

[''big''，''old''，''green'']

[''small ''，''old''，''green'']

[''medium''，''small''，''green'']

[''big''，''new''，''blue'']

[''small''，''new''，''blue'']

[''medium''，''new''，''blue'']

[''big''，''new''，''gr een'']

[''small''，''new''，''green'']

[''medium''，''new' '，''green'']


我可以嵌套for ... in循环，但是正在寻找一种Pythonic方式

来做这件事。想法？

解决方案

-----原帖---- -

来自：py********************************@python.org [mailto ：python-

li*************************@python.org]代表布雷尔

发送时间：2008年1月16日星期三下午2:15

要： py *********@python.org

主题：从列表中创建独特的组合


我有三个列表..例如


a = [''big''，''small''，''medium''];

b = [''old' '，''new''];

c = [''blue''，''green''];


我想拿这些和结束他们所有的组合

创建如下列表

[''big''，''old''，''blue'']

[''小''，''旧''，''蓝'''

[''我dium''，''old''，''blue'']

[''big''，''old''，''green'']

[''small''，''old''，''green'']

[''medium''，''small''，''green'']

[''big''，''new''，''blue'']

[''small''，''new''，''blue'' ]

[''中''，''新''''''蓝色'']

[''大''，''新''，' 'green'']

[''small''，''new''，''green'']

[''medium''，''new ''，''green'']


我可以在循环中嵌套...但是正在寻找一种Pythonic方式

这样做。想法？

http：/ /www.python.org/dev/peps/pep-0202/

1月16日上午11:33，Reedick ，安德鲁 < jr9 ... @ ATT.COMwrote：

-----原始消息-----

来自：python-list-bounces + jr9445 = att .... @ python.org [mailto：python-

list-bounces + jr9445 = att .... @ python .org]代表布雷尔

发送时间：2008年1月16日星期三下午2:15

收件人：python-l ... @ python.org

主题：从列表中创建唯一组合

我有三个列表...例如

< blockquote class =post_quotes>
a = [''big''，''small''，''medium''];

b = [''old''，''新的''];

c = [''blue''，''green''];

我想拿这些并最终获得所有组合

创建如下列表

[''big''，''old''，''blue'']

[''小''，''旧''，''蓝''' ]

[''中''，''旧''，''蓝'''

[''大''，''老''，' 'green'']

[''small''，''old''，''green'']

[''medium''，''small ''，''绿色'']

[''大''，''新'''''蓝色'']

[''小'' ，''new''，''blue'']

[''medium''，''new''，''blue'']

[' 'big''，''new''，''green'']

[''small''，''new''，''green'']

[''medium''，''new''，''green'']

我可以嵌套for ... in循环，但是正在寻找一个Pythonic方式

来做这件事。想法？

http：/ /www.python.org/dev/peps/pep-0202/

感谢您的回复。我从来没有意识到你可以像这样使用列表

理解...太棒了！

我可以嵌套for ... in循环，但是正在寻找一种Pythonic方式

来做这件事。想法？

我发现嵌套for循环非常Pythonic。明确比隐含更好，

和简单比复杂更好。


问候，

马丁

I have three lists... for instance

a = [''big'', ''small'', ''medium''];
b = [''old'', ''new''];
c = [''blue'', ''green''];

I want to take those and end up with all of the combinations they
create like the following lists
[''big'', ''old'', ''blue'']
[''small'', ''old'', ''blue'']
[''medium'', ''old'', ''blue'']
[''big'', ''old'', ''green'']
[''small'', ''old'', ''green'']
[''medium'', ''small'', ''green'']
[''big'', ''new'', ''blue'']
[''small'', ''new'', ''blue'']
[''medium'', ''new'', ''blue'']
[''big'', ''new'', ''green'']
[''small'', ''new'', ''green'']
[''medium'', ''new'', ''green'' ]

I could do nested for ... in loops, but was looking for a Pythonic way
to do this. Ideas?

解决方案

-----Original Message-----
From: py********************************@python.org [mailto:python-
li*************************@python.org] On Behalf Of breal
Sent: Wednesday, January 16, 2008 2:15 PM
To: py*********@python.org
Subject: Creating unique combinations from lists

I have three lists... for instance

a = [''big'', ''small'', ''medium''];
b = [''old'', ''new''];
c = [''blue'', ''green''];

I want to take those and end up with all of the combinations they
create like the following lists
[''big'', ''old'', ''blue'']
[''small'', ''old'', ''blue'']
[''medium'', ''old'', ''blue'']
[''big'', ''old'', ''green'']
[''small'', ''old'', ''green'']
[''medium'', ''small'', ''green'']
[''big'', ''new'', ''blue'']
[''small'', ''new'', ''blue'']
[''medium'', ''new'', ''blue'']
[''big'', ''new'', ''green'']
[''small'', ''new'', ''green'']
[''medium'', ''new'', ''green'' ]

I could do nested for ... in loops, but was looking for a Pythonic way
to do this. Ideas?

http://www.python.org/dev/peps/pep-0202/

On Jan 16, 11:33 am, "Reedick, Andrew" <[e-mail]:

-----Original Message-----
From: python-list-bounces+jr9445=[e-mail] [mailto:python-
list-bounces+jr9445=[e-mail]] On Behalf Of breal
Sent: Wednesday, January 16, 2008 2:15 PM
To: [e-mail]
Subject: Creating unique combinations from lists

I have three lists... for instance

a = [''big'', ''small'', ''medium''];
b = [''old'', ''new''];
c = [''blue'', ''green''];

I want to take those and end up with all of the combinations they
create like the following lists
[''big'', ''old'', ''blue'']
[''small'', ''old'', ''blue'']
[''medium'', ''old'', ''blue'']
[''big'', ''old'', ''green'']
[''small'', ''old'', ''green'']
[''medium'', ''small'', ''green'']
[''big'', ''new'', ''blue'']
[''small'', ''new'', ''blue'']
[''medium'', ''new'', ''blue'']
[''big'', ''new'', ''green'']
[''small'', ''new'', ''green'']
[''medium'', ''new'', ''green'' ]

I could do nested for ... in loops, but was looking for a Pythonic way
to do this. Ideas?

http://www.python.org/dev/peps/pep-0202/

Thanks for the reply. I never realized you could use list
comprehension like this... AWESOME!

I could do nested for ... in loops, but was looking for a Pythonic way

to do this. Ideas?

I find nested for loops very Pythonic. Explicit is better than implicit,
and simple is better than complex.

Regards,
Martin

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