OS X下的sqlite / PHP [英] sqlite/PHP under OS X
问题描述
运行10.5.3。我正在尝试使用sqlite
调用创建一个PHP命令行脚本。但它在第一个这样的（sqlite_open）失败了，说打电话给
undefined function sqlite_open ...。
phpinfo（）告诉我sqlite支持已启用。
我缺少什么？
TIA - tim
Running 10.5.3. I''m trying to make a PHP command line script with sqlite
calls. But it fails at the first such (sqlite_open), saying "call to
undefined function sqlite_open ...".
phpinfo() tells me that sqlite support is enabled.
What am I missing?
TIA - tim
推荐答案
Tim Streater写道：
Tim Streater wrote:
运行10.5.3。我正在尝试使用sqlite
调用创建一个PHP命令行脚本。但它在第一个这样的（sqlite_open）失败了，说打电话给
undefined function sqlite_open ...。
phpinfo（）告诉我sqlite支持已启用。
我缺少什么？
TIA - tim
Running 10.5.3. I''m trying to make a PHP command line script with sqlite
calls. But it fails at the first such (sqlite_open), saying "call to
undefined function sqlite_open ...".
phpinfo() tells me that sqlite support is enabled.
What am I missing?
TIA - tim
这里的东西没有任何意义。如果phpinfo（）显示SQL Lite是启用了
，那么将不会定义sqlite_open（）。
我知道这听起来很愚蠢 - 但是你执行的是来自
的phpinfo（）与您调用sqlite_open（）的位置相同？也就是说，如果
sqlite_open（）调用是在Web应用程序中，那么你的phpinfo（）是否是从同一网站加载的
？或者，如果这是一个CLI应用程序，你是否从另一个CLI调用phpinfo（）
？
-
= =================
删除x来自我的电子邮件地址
Jerry Stuckle
JDS计算机培训公司
js ******* @ attglobal.net
==================
Something here doesn''t make any sense. If phpinfo() shows SQL Lite is
enabled, then sqlite_open() will not be defined.
I know this sounds stupid - but are you executing your phpinfo() from
the same location that you''re calling sqlite_open()? That is, if the
sqlite_open() call is in a web application, is your phpinfo() being
loaded from the same WEBSITE? Or, if this is a CLI application, are you
calling phpinfo() from another CLI?
--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
js*******@attglobal.net
==================
在文章< g3 ********** @ registered.motzarella.org>中，
Jerry Stuckle< js * ****** @attglobal.netwrote：
In article <g3**********@registered.motzarella.org>,
Jerry Stuckle <js*******@attglobal.netwrote:
Tim Streater写道：
Tim Streater wrote:
运行10.5。 3。我正在尝试使用sqlite
调用创建一个PHP命令行脚本。但它在第一个这样的（sqlite_open）失败了，说打电话给
undefined function sqlite_open ...。
phpinfo（）告诉我sqlite支持已启用。
我缺少什么？
TIA - tim
Running 10.5.3. I''m trying to make a PHP command line script with sqlite
calls. But it fails at the first such (sqlite_open), saying "call to
undefined function sqlite_open ...".
phpinfo() tells me that sqlite support is enabled.
What am I missing?
TIA - tim
这里的东西没有任何意义。如果phpinfo（）显示SQL Lite是启用了
，那么将不会定义sqlite_open（）。
Something here doesn''t make any sense. If phpinfo() shows SQL Lite is
enabled, then sqlite_open() will not be defined.
这是一个额外的不是那里？ :-)
Is that an extra "not" there? :-)
我知道这听起来很愚蠢 - 但你是从
执行你的phpinfo（）你在同一个地方调用sqlite_open（）？也就是说，如果
sqlite_open（）调用是在Web应用程序中，那么你的phpinfo（）是否是从同一网站加载的
？或者，如果这是一个CLI应用程序，你是否从另一个CLI调用phpinfo（）
？
I know this sounds stupid - but are you executing your phpinfo() from
the same location that you''re calling sqlite_open()? That is, if the
sqlite_open() call is in a web application, is your phpinfo() being
loaded from the same WEBSITE? Or, if this is a CLI application, are you
calling phpinfo() from another CLI?
一个PHP脚本只包含phpinfo调用。另一个只有一个
sqlite_open调用。两者都在我的主目录中。我从终端
窗口开始运行：
promptphp somefile.php
所以 - 那个'是的。
One PHP script contains just the phpinfo call. The other just has an
sqlite_open call. Both in my home directory. I run both from a Terminal
window by going:
promptphp somefile.php
So - that''s it.
6月20日上午10:52，Tim Streater< timstrea ... @ waitrose.comwrote：
On Jun 20, 10:52 am, Tim Streater <timstrea...@waitrose.comwrote:
文章< g3etrb
In article <g3etrb
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