如何阅读短信和删除不保存在收件箱中 [英] How to read sms and delete without save in inbox

问题描述

我想读短信，从特定的号码，然后删除，但不保存在收件箱中。下面是我的code的读取短信但这code保存的短信收件箱。 我该怎么办删除特定号码短信读取之后呢？

 公共类SmsReceiver扩展的BroadcastReceiver
{
公共静态字符串SMSstr;
公共无效的onReceive（上下文的背景下，意图意图）
{
    // ---得到通过短信---
    捆绑包= intent.getExtras（）;
    SmsMessage []封邮件= NULL;
    字符串str =;

    如果（捆绑！= NULL）
    {
        // ---检索收到的短信---
        [对象]的PDU =（对象[]）bundle.get（的PDU）;
        封邮件=新SmsMessage [pdus.length]
        的for（int i = 0; I＆LT; msgs.length;我++）{
            封邮件[I] = SmsMessage.createFromPdu（（字节[]）的PDU [I]）;

            字符串普农=封邮件[I] .getOriginatingAddress（）;

            STR + =封邮件[I] .getMessageBody（）的toString（）。
            如果（15555215556.equals（普农））
            {
                //删除code到这里

                意图L =新的意图（背景下，AgAppMenu.class）;
                l.putExtra（味精，STR）;
                l.setFlags（Intent.FLAG_ACTIVITY_NEW_TASK）;
                context.startActivity（升）;
                Toast.makeText（上下文中，SucessFull登录，Toast.LENGTH_SHORT）.show（）;
            }
        }


         ＆LT;接收机器人：SmsReceiver名称=机器人：启用=真正的＆GT;
     ＆所述;！ - ＆所述;意图滤光器＆gt;  - ＆GT;
            ＆LT;意图过滤器的Andr​​oid版本：优先=1000＆GT;
            ＆lt;作用机器人：名称=
                android.provider.Telephony.SMS_RECEIVED/＆GT;
       ＆所述; /意图滤光器＆gt;
    ＆LT; /接收器＆GT;
 

解决方案

如果你想删除的邮件只需调用 abortBroadcast（）后您检查所需的源！

I want to read a sms from specific number then delete without saving it in inbox. Below is my code which read sms but this code saves the SMS in the inbox. How can I do delete a sms from specific number after read it?

public class SmsReceiver extends BroadcastReceiver 
{
public static  String SMSstr;
public void onReceive(Context context, Intent intent) 
{
    //---get the SMS message passed in---
    Bundle bundle = intent.getExtras();        
    SmsMessage[] msgs = null;
    String str = "";  

    if (bundle != null)
    {
        //---retrieve the SMS message received---
        Object[] pdus = (Object[]) bundle.get("pdus");
        msgs = new SmsMessage[pdus.length];            
        for (int i=0; i<msgs.length; i++){
            msgs[i] = SmsMessage.createFromPdu((byte[])pdus[i]);                

            String phNum = msgs[i].getOriginatingAddress();  

            str += msgs[i].getMessageBody().toString();
            if ("15555215556".equals(phNum))
            {
                // delete code goes here

                Intent l = new Intent(context,AgAppMenu.class);
                l.putExtra("msg",str);
                l.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
                context.startActivity(l);
                Toast.makeText(context, "SucessFull Login", Toast.LENGTH_SHORT).show();
            }
        }


         <receiver android:name=".SmsReceiver" android:enabled="true"> 
     <!--       <intent-filter >-->
            <intent-filter android:priority="1000"> 
            <action android:name=
                "android.provider.Telephony.SMS_RECEIVED" /> 
       </intent-filter> 
    </receiver>

解决方案

If you want to delete the message simply call the abortBroadcast() after you check for the desired source!

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