如何查找和处理最大和最小数字？ [英] How to find and deal with maximum and minimum numbers?
问题描述
我是C初学者。
我想写一个C.
伪代码是这样的：
用户输入一些数字（使用-1结束）
编译器查找并删除最大和最小数字
然后平均剩余数字
最后打印结果
提前致谢!!!
Hi, I''m a C beginner.
I want to write a C.
The pseudocodes are like this:
User enters some numbers (use -1 to end)
The compiler find and delete the maximum and minimum numbers
Then average remained numbers
Finally print the result
Thanks in advance!!!
推荐答案
zj ****** @ 163.com 写道：
我是C初学者。
我想写一个C.
伪代码是这样的：
用户输入一些数字（使用-1结束）
编译器查找并删除最大和最小数字
然后平均剩余数字
最后打印结果
提前致谢!!!
Hi, I''m a C beginner.
I want to write a C.
The pseudocodes are like this:
User enters some numbers (use -1 to end)
The compiler find and delete the maximum and minimum numbers
Then average remained numbers
Finally print the result
Thanks in advance!!!
做你自己的作业。
如果你不自己动手做作业就可以教你了吗？ >
你将不会学到任何东西
-
jacob navia
jacob at jacob point remcomp point fr
logiciels / informatique
http：//www.cs .virginia.edu / ~lcc-win32
zj * *****@163.com 写道：
我是C初学者。
我想要写一个C.
伪代码是这样的：
用户输入一些数字（用-1结束）
编译器查找并删除最大和最小数字
然后平均剩余数字
最后打印结果
提前致谢！ ！
Hi, I''m a C beginner.
I want to write a C.
The pseudocodes are like this:
User enters some numbers (use -1 to end)
The compiler find and delete the maximum and minimum numbers
Then average remained numbers
Finally print the result
Thanks in advance!!!
对我来说看起来不像伪代码，就像（家庭作业）任务一样。也许
以下内容有助于您入门：
读取数量
counter = 1
max = min = sum = number
循环
读数
counter ++
如果数字最大
max =数字
否则如果数字< min
min =数字
总和+ =数字
重复而数字不是-1
总和 - =（最小值+最大值）
计数器 - = 2 / *表示最小值最大值不再存在* /
结果=总和/计数器
打印结果
再见，Jojo
Doesn''t look like pseudocode to me, mor like a (homework) task. Maybe the
following helps to get you started:
read number
counter=1
max = min = sum = number
loop
read number
counter++
if number max
max = number
else if number < min
min = number
sum += number
repeat while number not -1
sum -= (min+max)
counter -=2 /* to account for min amd max not being in anymore */
result = sum/counter
print result
Bye, Jojo
Joachim Schmitz说：
Joachim Schmitz said:
zj******@163.com 写道：
>我是C初学者。
我想写一个C.
伪代码是这样的：
用户输入一些数字（使用-1结束）
编译器查找并删除最大和最小数字
然后平均剩余数字
最后打印结果
提前致谢!! ！
>Hi, I''m a C beginner.
I want to write a C.
The pseudocodes are like this:
User enters some numbers (use -1 to end)
The compiler find and delete the maximum and minimum numbers
Then average remained numbers
Finally print the result
Thanks in advance!!!
对我来说看起来不像伪代码，就像（家庭作业）任务一样。也许
以下内容有助于您入门：
读取数量
counter = 1
max = min = sum = number
循环
读数
counter ++
如果数字最大
max =数字
否则如果数字< min
min =数字
总和+ =数字
重复而数字不是-1
总和 - =（最小值+最大值）
计数器 - = 2 / *表示最小值最大值不再存在* /
结果=总和/计数器
打印结果
Doesn''t look like pseudocode to me, mor like a (homework) task. Maybe the
following helps to get you started:
read number
counter=1
max = min = sum = number
loop
read number
counter++
if number max
max = number
else if number < min
min = number
sum += number
repeat while number not -1
sum -= (min+max)
counter -=2 /* to account for min amd max not being in anymore */
result = sum/counter
print result
对不起，我不认为这回答了OP的问题。他想要
*编译器*来查找和删除最大和最小数字。
Tricky - 但我认为显而易见的方法是编写代码生成器
包含受预处理器保护的答案的硬编码列表
定义（或者，如果不允许，则使用if（0）然后打开为
你可以找到许多优化），然后向编译器发出外壳。
-
Richard Heathfield< http：//www.cpax.org.uk>
电子邮件：-http：// www。 + rjh @
谷歌用户：< http://www.cpax.org.uk/prg/writings/googly.php>
Usenet是一个奇怪的放置" - dmr 1999年7月29日
Sorry, but I don''t think that answers the OP''s question. He wants the
*compiler* to find and delete the maximum and minimum numbers.
Tricky - but I suppose the obvious approach is to write a code generator
containing a hard-coded list of the answers protected by preprocessor
definitions (or, if that''s not allowed, use if(0) and then switch on as
many optimisations as you can find), and then shell out to the compiler.
--
Richard Heathfield <http://www.cpax.org.uk>
Email: -http://www. +rjh@
Google users: <http://www.cpax.org.uk/prg/writings/googly.php>
"Usenet is a strange place" - dmr 29 July 1999
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