函数返回字符串数组 [英] function to return string array

问题描述

我创建了一个函数，你发送一个字符串，并根据空格进行标记，所以我给它发一个字符串给它返回一个字符串数组，但是在函数的声明中它表示


错误C2470：''splitter''：看起来像一个函数定义，但是没有参数列表;跳过明显的身体

和

错误C2092：''splitter''数组元素类型无法正常运行


我的标题是


字符串拆分器[]（字符串行）


i前几天读取的返回值可以是任何长度，只要它的一个对象， int，string，array，只要它是一个对象，那么我做错了什么？


提前感谢

解决方案

< blockquote>

i创建了一个函数，你发送一个字符串，并根据空格进行标记，所以我给它发一个字符串给它返回一个字符串数组，但是在声明中它说的功能


错误C2470：''splitter''：看起来像一个函数定义，但是没有参数列表;跳过明显的身体

和

错误C2092：''splitter''数组元素类型无法正常运行


我的标题是


字符串拆分器[]（字符串行）


i前几天读取的返回值可以是任何长度，只要它的一个对象， int，string，array，只要它是一个对象，那么我做错了什么？


提前感谢

，因为spliter []，你不能将数组元素类型作为返回值。将其更改为* spliter并且它将起作用。


Savage

<非常感谢

非常感谢：D它工作了


一切正常，功能明智，但是当我打电话给它时，我收到了这个错误


警告C4172：返回本地变量的地址或临时的


你真高兴知道为什么会这样吗？非常感谢

我想我必须用公共功能宣布它，我做了，但现在我得到一个新的错误，


1> retrieveGeoCmdCmd.obj：错误LNK2019：未解析的外部符号" class std :: basic_string< char，struct std :: char_traits< char>，class std :: allocator< char> > __cdecl splitter（类std :: basic_string< char，struct std :: char_traits< char>，class std :: allocator< char>>）" （？分离器@@ YA？AV？

i created a function which u send a string, and it tokenizes according to spaces, so i send it a string for it to return me a string array, but on the declaration of the function it says

error C2470: ''splitter'' : looks like a function definition, but there is no parameter list; skipping apparent body
and
error C2092: ''splitter'' array element type cannot be function

and my header is

string splitter[](string line)

i read the other day that the return value could be anythin as long as its one object ,int, string, array, as long as its one object, so what am i doing wrong?

thanks in advance

解决方案

i created a function which u send a string, and it tokenizes according to spaces, so i send it a string for it to return me a string array, but on the declaration of the function it says

error C2470: ''splitter'' : looks like a function definition, but there is no parameter list; skipping apparent body
and
error C2092: ''splitter'' array element type cannot be function

and my header is

string splitter[](string line)

i read the other day that the return value could be anythin as long as its one object ,int, string, array, as long as its one object, so what am i doing wrong?

thanks in advance

it''s because of spliter[],you cannot have array element type as a return value.Change it to *spliter and it will work.

Savage

thanks a lot :D it worked

it all worked, function wise, but when i call it, i get this error

warning C4172: returning address of local variable or temporary

do u happpen to know why that is?? thanks a lot again

well i figured i had to have it declared withthe public functions, which i did, but now i get a new error,

1>retrieveGeoCmdCmd.obj : error LNK2019: unresolved external symbol "class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> > __cdecl splitter(class std::basic_string<char,struct std::char_traits<char>,class std::allocator<char> >)" (?splitter@@YA?AV?

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