小问题 [英] Little Problem
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问题描述
我有三个号码 - 1,2和& 3.
三个中随机选择的一个存储在''var1''中，另一个
随机选择一个存储在''var2''中。
如何找出遗留的数字？
我尝试了一段时间但我无法得到它工作......
TIA
I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in ''var1'', and another
randomly selected one is in ''var2''.
How do I find out the number that is left over?
I tried a while loop but I couldn''t get it to work...
TIA
推荐答案
fsd，
我要做的是将值存储在ArrayList中。当你随机选择
数字时，将它们从ArrayList中删除并放入一个新的
集合中。这将要求您每次更改所选随机
数字的范围（第一次从范围中选择随机数
1-3，然后1-2等等）。当你有足够的
数字时，你必须停下来。然后，在ArrayList中留下的是什么是
未被选中。
希望这会有所帮助。
-
- Nicholas Paldino [.NET / C＃MVP]
- mv * @ spam。 guard.caspershouse.com
" fsd" < sg@hotmial.com>在留言中写道
news：bs ************ @ ID-83837.news.uni-berlin.de ...
fsd,
What I would do is store the values in an ArrayList. When you pick the
numbers randomly, remove them from the ArrayList and place into a new
collection. This would require you to change the range of selected random
numbers every time (the first time you pick a random number from the range
1-3, then 1-2, etc, etc). You just have to stop when you have enough
numbers selected. Then, whatever is left over in the ArrayList is what was
not selected.
Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard.caspershouse.com
"fsd" <sg@hotmial.com> wrote in message
news:bs************@ID-83837.news.uni-berlin.de...
I有三个数字 - 1,2和& 3.
随机选择的三个存储在''var1''中，另一个随机选择的存储在''var2''中。
我如何找出剩余的数字？
我尝试了一段时间但我无法让它工作......
TIA
I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in ''var1'', and another
randomly selected one is in ''var2''.
How do I find out the number that is left over?
I tried a while loop but I couldn''t get it to work...
TIA
这样的东西（伪代码）：
var1 = Random（3）;
var2 =随机（3）;
而（var2 == var1）
{
var2 =随机（ 3）;
}
-
Dmitriy Lapshin [C＃/ .NET MVP]
X-Unity Test Studio
http：// x- unity.miik.com.ua/teststudio.aspx
将单元测试的强大功能带到VS .NET IDE
" fsd" < sg@hotmial.com>在留言中写道
news：bs ************ @ ID-83837.news.uni-berlin.de ...
Something like this (pseudo-code):
var1 = Random(3);
var2 = Random(3);
while (var2 == var1)
{
var2 = Random(3);
}
--
Dmitriy Lapshin [C# / .NET MVP]
X-Unity Test Studio
http://x-unity.miik.com.ua/teststudio.aspx
Bring the power of unit testing to VS .NET IDE
"fsd" <sg@hotmial.com> wrote in message
news:bs************@ID-83837.news.uni-berlin.de...
I有三个数字 - 1,2和& 3.
随机选择的三个存储在''var1''中，另一个随机选择的存储在''var2''中。
我如何找出剩余的数字？
我尝试了一段时间但我无法让它工作......
TIA
I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in ''var1'', and another
randomly selected one is in ''var2''.
How do I find out the number that is left over?
I tried a while loop but I couldn''t get it to work...
TIA
fsd写道：
我有三个数字 - 1,2和& 3.
随机选择的三个存储在''var1''中，另一个随机选择的存储在''var2''中。
我如何找出剩余的数字？
我尝试了一段时间但我无法让它工作......
TIA
I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in ''var1'', and another
randomly selected one is in ''var2''.
How do I find out the number that is left over?
I tried a while loop but I couldn''t get it to work...
TIA
一起添加var1和var2
伪代码;
开关（var1 + var2）
案例3：剩下三个
案例4：剩下两个
案例5：一个是左
Add var1 and var2 together
psuedo code;
switch(var1 + var2)
case 3: three is left
case 4: two is left
case 5: one is left
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