寻求条件表达 [英] conditional expression sought

问题描述

如果bool（B_i）== True为1< = i< = n且j为最小i，则bool（A_j）== True，

则评估（A_1和B_1） ）或...或（A_n和B_n）返回B_j而不评估任何其他B_i的
。这是一种非常有用的表达方式，即使有一个我用

bool（B_i）== False，我也希望能够使用类似的东西。我唯一能想到的就是（（A_1和[B_1]）

或......或（A_n和[B_n]））[0]，我不可能对此明显感到满意

的原因。有人知道表达这个的好方法吗？任何帮助都会很多

欣赏。


和平

If bool(B_i)==True for 1<=i<=n and j is the smallest i with bool(A_j)==True,
then the evaluation of (A_1 and B_1) or ... or (A_n and B_n) returns B_j without
evaluating any other B_i. This is such a useful mode of expression that I would
like to be able to use something similar even when there is an i with
bool(B_i)==False. The only thing I can think of by myself is ( (A_1 and [B_1])
or ... or (A_n and [B_n]) )[0], and I can''t be satisfied with that for obvious
reasons. Does anybody know a good way to express this? Any help will be mucho
appreciado.

Peace

推荐答案

自是真还是假

还可以评估为1和0

你可以使用二元运算符

|和&

for or和and

since True and False
can also evaluate as 1 and 0
you can use the binary operators
| and &
for or and and respectively

F类：
.... a = 5

.... def b（个体经营）：

.... self.a = 4

....返回True

.... def a（self）：

.... self.a = 1

....返回False

.... g = F（）
ga（）& g.b（）
False g.a

class F: .... a = 5
.... def b(self):
.... self.a = 4
.... return True
.... def a(self):
.... self.a = 1
.... return False
.... g = F()
g.a() & g.b() False g.a

" Elaine Jackson" < EL *************** @ home.com>在消息中写道

news：pRbSb.330334

4
"Elaine Jackson" <el***************@home.com> wrote in message
news:pRbSb.330334

ts4.37644@pd7tw3no ...如果bool（B_i）== True为1< = i< = n和j是最小的i，带有
bool（A_j）== True，然后评估（A_1和B_1）或......或（A_n和B_n）返回B_j
而不评估任何其他B_i 。这是一种非常有用的表达方式，即使有一个带有
bool（B_i）== False的i，我也希望能够使用类似的东西。我唯一能想到的就是（（A_1和
[B_1]）或......或（A_n和[B_n]））[0]，我不能满足于此
显而易见的原因。有人知道表达这个的好方法吗？任何帮助将是
mucho appreciado。

和平

ts4.37644@pd7tw3no... If bool(B_i)==True for 1<=i<=n and j is the smallest i with bool(A_j)==True, then the evaluation of (A_1 and B_1) or ... or (A_n and B_n) returns B_j without evaluating any other B_i. This is such a useful mode of expression that I would like to be able to use something similar even when there is an i with
bool(B_i)==False. The only thing I can think of by myself is ( (A_1 and [B_1]) or ... or (A_n and [B_n]) )[0], and I can''t be satisfied with that for obvious reasons. Does anybody know a good way to express this? Any help will be mucho appreciado.

Peace

Elaine Jackson写道：

Elaine Jackson wrote:

如果bool（B_i）== True为1< = i< = n而j是最小的i与bool（A_j）== True，
则评估（A_1和B_1）或......或（A_n和B_n）返回B_j而不评估任何其他B_i。这是一种非常有用的表达方式，即使有一个带有
bool（B_i）== False的i，我也希望能够使用类似的东西。我唯一能想到的就是（（A_1和[B_1]）
或......或（A_n和[B_n]））[0]，我不能满足于此显而易见的原因。有人知道表达这个的好方法吗？任何帮助都会很有意思。

If bool(B_i)==True for 1<=i<=n and j is the smallest i with bool(A_j)==True,
then the evaluation of (A_1 and B_1) or ... or (A_n and B_n) returns B_j without
evaluating any other B_i. This is such a useful mode of expression that I would
like to be able to use something similar even when there is an i with
bool(B_i)==False. The only thing I can think of by myself is ( (A_1 and [B_1])
or ... or (A_n and [B_n]) )[0], and I can''t be satisfied with that for obvious
reasons. Does anybody know a good way to express this? Any help will be mucho
appreciado.

为什么不写一个单元测试来演示你想要的行为呢？

那么它很可能对于某个人来说，显而易见的是你的问题和

可能的解决方案是什么。


干杯，


// m

Why not write a unit test that demonstrates the behavior you want?
It''ll then likely be obvious to someone both what your problem is and
what a likely solution is.

Cheers,

// m

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