string.seach（）RegEx问题 [英] string.seach() RegEx question

问题描述

如果我想找一个表达式，foo，我可以做类似

这样的事情：


rExp = / foo / gi;

if（results.search（rExp）> -1）{


并且一切正常。


但是，如果我希望我的搜索词是一个变量，那么吧：

var bar =" foo";

i当我尝试将条形连接到正则表达式时得到错误。


我对正则表达式不是很好，或者对于那个

问题的JavaScript，但显然rExp不是字符串或者它会在引号中，

并且它不是整数或布尔值。那么它的数据类型是什么？以及如何将
合并到变量条中，使其为/ bar / gi？


谢谢，

L ^ K

解决方案

Lord Khaos于2003年12月16日在comp.lang.javascript中写道 ：

如果我想找一个表达式，foo，我可以做类似
这样的事情：

rExp = / foo / gi;
if（结果） .search（rExp）> -1）{

并且一切正常。

但是，如果我希望我的搜索词是变量，bar：
var bar =" foo";
当我尝试将条形图连接到正则表达式时，我收到错误。

我对正则表达式或JavaScript不是很好<事实上，但显然rExp不是一个字符串，或者它将在引号中，
并且它不是整数或布尔值。那么它的数据类型是什么？以及如何将变量栏合并到它中以便它是/ bar / gi？

< script>

函数TestDemo（ teststr，s）{

re = new RegExp（teststr，gi）;

return re.test（s）;

};


bar =" foo";

alert（TestDemo（bar，" foobar"））;

< / script>

-

Evertjan。

荷兰。

（请更改x' 我的电子邮件地址中的点

Lord Khaos写道：

如果我想找一个表达式，foo，我可以这样做：

rExp = / foo / gi;
if（results.search（rExp）> -1）{
var bar =" foo" ;;
我得到错误时我尝试将条形图整合到正则表达式中。

我对普通表达不是很好对于那个问题的ns或JavaScript，但显然rExp不是字符串，或者它将在引号中，
并且它不是整数或布尔值。那么它的数据类型是什么？以及如何将变量栏合并到它中以便它是/ bar / gi？

谢谢，
L ^ K

var bar =" foo";

var rExp = new RegExp（bar，" gi"）;

var results =" blah blah foo blah" ;;

if（results.search（rExp）> -1）{

//请注意：

// " if（rExp.test（results））{"

//如果你正在做的就是测试一场比赛的速度更快

//你和你不关心最终的比赛

//当结果为空时它也有效

alert（" yes"）;

}


另请注意，如果[bar]将包含任何特殊的正则表达式实体

（\d，\ s等），则需要将字符串字符转义规则应用于它们：


var bar =" \d" ;; //这个正则表达式会找到一个数字吗？

var rExp = new RegExp（bar）;

var result =" 1";

alert（rExp.test（result））; //嗯，这是假的


var bar =" \\d" ;; //不，这会找到一个数字

var rExp = new RegExp（bar）;

var result =" 1";

alert（rExp.test（result））; //现在它的确如此应该是


如果你在循环中设置[bar]，你可以避免创建一个新对象

每次使用compile（）方法：


var rExp = new RegExp（）;

for（var i = 0 ; i< loop.length; i ++）{

rExp.compile（yourArray [i]）;

if（rExp.test（result））{

// ...

}


-

| Grant Wagner< gw ***** @ agricoreunited.com>


*客户端Javascript和Netscape 4 DOM参考可从以下位置获得：

*
http：// devedge .netscape.com / library / ... ce / frames.html


* Internet Explorer DOM参考资料：

*
http://msdn.microsoft.com/研讨会/ a ... ence_entry.asp


* Netscape 6/7 DOM参考资料于：

* http://www.mozilla.org/docs/dom/domref/

*为Netscape 7 / Mozilla升级JavaScript的提示

* http：//www.mozil la.org/docs/web-deve...upgrade_2.html

谢谢你们的帮助，这正是我所寻求的 - 我

想想??? :)


我实际上在做的是尝试编写ASP / JavaScript，其中<​​br />
用户在表单中输入搜索词。我有以下内容：

=========================

<％@语言= QUOT; JavaScript的" ％>

<！ - #include file =" dsnless_db.inc" - >

<％

var search = Request.QueryString（" term"）;

var my_ids = new Array（ ）;

var i = 0;

sql ="选择名称，描述，来自产品的ID" ;;

RS = Connection.Execute （sql）;

rExp = new RegExp（search，gi）;

do {

results = RS.Fields（" ;描述"）。值;

results2 = RS.Fields（" name"）。value;

if（results.search（rExp）> -1 | | results2.search（rExp）> -1）{

my_ids [i] = RS.Fields（" id"）。value;

i ++}

RS.MoveNext;

} while（！RS.EOF）;


var number = my_ids.length;

if（number> 0）{％>

< html>< body>

<％

for（i = 0; i< number; i ++）{

sql =" SELECT * FROM products WHERE id =" + my_ids [i];

RS = Connection.Execute（sql）;％>

<％

do {％> < b>产品＃

<％Response.write（RS.Fields（" id"））;％>

< / b>< P>

< br><％Response.write（RS.Fields（" name"））; ％>

< br>

<％Response.write（RS.Fields（" description"））;

％ >

< br><％Response.write（RS.Fields（" price"））; ％>

< hr>< / P>

<％RS.MoveNext;

} while（！RS.EOF ）;

}

}

Connection.Close;


％>

------------------------

这个有效，再次感谢你，但我很纳闷现在如果.test会比搜索更好
。


TIA，

L ^ K

If I am trying to find an expression, foo, I can do something like
this:

rExp = /foo/gi;
if(results.search(rExp) > -1){

and all work fine.

however, if I want my search term to be a variable, bar:
var bar= "foo";
i get error when I try to concatinate bar into the regex.

I''m not very good with Regular expressions, or JavaScript for that
matter, but apparently rExp is not a string or it would be in quotes,
and it isn''t an integer or boolean. So what is it''s data type? and how
would I merge the variable bar into it so that it is /bar/gi?

Thanks,
L^K

解决方案

Lord Khaos wrote on 16 dec 2003 in comp.lang.javascript:

If I am trying to find an expression, foo, I can do something like
this:

rExp = /foo/gi;
if(results.search(rExp) > -1){

and all work fine.

however, if I want my search term to be a variable, bar:
var bar= "foo";
i get error when I try to concatinate bar into the regex.

I''m not very good with Regular expressions, or JavaScript for that
matter, but apparently rExp is not a string or it would be in quotes,
and it isn''t an integer or boolean. So what is it''s data type? and how
would I merge the variable bar into it so that it is /bar/gi?

<script>
function TestDemo(teststr, s){
re = new RegExp(teststr,"gi");
return re.test(s);
};

bar = "foo";
alert( TestDemo(bar, "foobar") );
</script>
--
Evertjan.
The Netherlands.
(Please change the x''es to dots in my emailaddress)

Lord Khaos wrote:

If I am trying to find an expression, foo, I can do something like
this:

rExp = /foo/gi;
if(results.search(rExp) > -1){

and all work fine.

however, if I want my search term to be a variable, bar:
var bar= "foo";
i get error when I try to concatinate bar into the regex.

I''m not very good with Regular expressions, or JavaScript for that
matter, but apparently rExp is not a string or it would be in quotes,
and it isn''t an integer or boolean. So what is it''s data type? and how
would I merge the variable bar into it so that it is /bar/gi?

Thanks,
L^K

var bar = "foo";
var rExp = new RegExp(bar, "gi");
var results = "blah blah foo blah";
if (results.search(rExp) > -1) {
// Please note:
// "if (rExp.test(results)) {"
// is faster if all you''re doing is testing for a match
// and you don''t care about the resulting matches
// it also works when results is null
alert("yes");
}

Also note that if [bar] is going to contain any special regex entities
(\d, \s, etc), you need to apply string character escaping rules to them:

var bar = "\d"; // this regex will find a digit right?
var rExp = new RegExp(bar);
var result = "1";
alert(rExp.test(result)); // hmm, it''s false

var bar = "\\d"; // no, this will find a single digit
var rExp = new RegExp(bar);
var result = "1";
alert(rExp.test(result)); // now it''s true like it''s supposed to be

If you''re setting [bar] in a loop, you can avoid creating a new object
each time by using the compile() method:

var rExp = new RegExp();
for (var i = 0; i < loop.length; i++) {
rExp.compile(yourArray[i]);
if (rExp.test(result)) {
// ...
}

--
| Grant Wagner <gw*****@agricoreunited.com>

* Client-side Javascript and Netscape 4 DOM Reference available at:
*
http://devedge.netscape.com/library/...ce/frames.html

* Internet Explorer DOM Reference available at:
*
http://msdn.microsoft.com/workshop/a...ence_entry.asp

* Netscape 6/7 DOM Reference available at:
* http://www.mozilla.org/docs/dom/domref/
* Tips for upgrading JavaScript for Netscape 7 / Mozilla
* http://www.mozilla.org/docs/web-deve...upgrade_2.html

Thank you both for the help, that is just what I was looking for- I
think ??? :)

What I''m actually doing is trying to write ASP/JavaScript where the
user enters a search term into a form. I have the following:
=========================
<% @Language="JavaScript" %>
<!-- #include file="dsnless_db.inc" -->
<%
var search= Request.QueryString("term");
var my_ids = new Array();
var i=0;
sql="select name, description, id from products";
RS=Connection.Execute(sql);
rExp = new RegExp(search, "gi");
do{
results = RS.Fields("description").value;
results2= RS.Fields("name").value;
if(results.search(rExp) > -1 || results2.search(rExp) > -1){
my_ids[i]=RS.Fields("id").value;
i++}
RS.MoveNext;
}while(!RS.EOF);

var number = my_ids.length;
if(number > 0){ %>
<html><body>
<%
for(i=0;i<number;i++){
sql="SELECT * FROM products WHERE id=" + my_ids[i];
RS=Connection.Execute(sql);%>
<%
do{ %><b>Product #
<%Response.write(RS.Fields("id"));%>
</b><P>
<br><% Response.write(RS.Fields("name")); %>
<br>
<% Response.write(RS.Fields("description"));
%>
<br><% Response.write(RS.Fields("price")); %>
<hr></P>
<% RS.MoveNext;
}while(!RS.EOF);
}
}
Connection.Close ;

%>
------------------------
This works, thank you again, but I''m wondering now if .test would be
better than search.

TIA,
L^K

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