合并JSON对象数组并使用Javascript进行排序 [英] Merge JSON Object arrays and sort with Javascript

问题描述

我有一个包含12个数组的JSON对象。不同地区的国家。我正在尝试将此数组合并到选择下拉菜单中。 JSON看起来像这样：

I have a JSON object with 12 arrays. Different regions of countries. I'm trying to merge this array into select dropdown menu. The JSON looks like this:

"latinamerica": [
        "Argentina",
        "Bolivia",
        "Brazil",
        "Chile",
        "Colombia",
        "Ecuador",
        "Paraguay",
        "Peru"
    ],
    "korea": ["South Korea"]

然后我打电话在JSON中：

Then I call in the JSON with:

    $.getJSON('js/countries.json', function(data) {

  var items = [];      

  items[0] = '<option value="0">Country</option>';

  $.each(data['latinamerica'], function(key, val) {
    items.push('<option value="'+ key +'">'+ val +'</option>');
  });
});

对Object中的每个数组执行此操作。问题是我想合并所有这些数组，按字母顺序对它们进行排序，但仍保持它们所关联的区域。所以基本上我会有一个所有国家的下拉列表，HTML看起来像：

Doing this for every array in the Object. Problem is I want to merge all these arrays, sort them alphabetically but still maintain what region they are associated with. So essentially I would have a dropdown of all the countries and the HTML would look like:

<option value="latinamerica">Argentina</option>
<option value="europe">Austria</option>

我尝试过连接但后来丢失了我的数组名称。建议？ TIA。

I've tried doing concat but then I lose my array names. Suggestions? TIA.

推荐答案

您基本上需要一个不同的模型来生成视图：

You basically need a different "model" to generate that "view":

var countries = [];
for (var region in data) {
  for (var i = 0, l = data[region].length; i < l; ++i) {  
    countries.push({ country: data[region][i], region: region });
  }
}

然后你对它进行排序：

countries.sort(function(a, b) {
  if (a.country < b.country) return -1;
  if (a.country > b.country) return 1;
  return 0;
});

然后你使用它：

var items = [];      

items.push('<option value="0">Country</option>');
for (var i = 0, l = countries.length; i < l; ++i) {
  items.push('<option value="'+ countries[i].region +'">'+ countries[i].country +'</option>');
}

（注意：所有这些代码都是未经测试的） 。

(NOTE: all this code is untested).

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