怎么写?? [英] how to write??
问题描述
大家好!
我的问题:
怎么写(在Builder C ++中)
10 ^( - b * z)
因为我不知道:(
感谢您的帮助..
johnnyB
janek写道:大家好!
我的问题:
如何写(在Builder C ++中)
10 ^( - b * z)
因为我不知道:(
如果我没有误会它是pow(10.0,b * z);你需要包括math.h
-
WW aka Attila
" janek"< si ****@poczta.gazeta.pl>写在消息中
news:bk ********** @ inews.gazeta.pl ...大家好!
我的问题:
如何写(在Builder C ++中)
10 ^( - b * z)
因为我不知道:(
感谢您的帮助..
johnnyB
我猜,但试试''std :: pow(10, - b * z) ''。
你有到#include< cmath>首先。
Buster写道:我猜,但试试''std :: pow(10, - b * z) ''。
你必须#include< cmath>第一个。
在我们再次讨论cmath / std :: vs. math / nostd之前我有
提出了后者有两个原因。一:不幸的是我已经看到了
编译器,其中包含一个cxxx标题确定是disater的配方。另一个
(不那么重要)是它也适用于C.
-
WW aka Attila
Hello all!
My question:
How to write (in Builder C++)
10^(-b*z)
cause i have no idea :(
Thanks for any help..
johnnyB
janek wrote:Hello all!
My question:
How to write (in Builder C++)
10^(-b*z)
cause i have no idea :(
If I am not mistaking it is pow(10.0, b*z); You need to include math.h
--
WW aka Attila
"janek" <si****@poczta.gazeta.pl> wrote in message
news:bk**********@inews.gazeta.pl...Hello all!
My question:
How to write (in Builder C++)
10^(-b*z)
cause i have no idea :(
Thanks for any help..
johnnyB
I''m guessing, but try ''std::pow (10, - b * z)''.
You have to #include <cmath> first.
Buster wrote:I''m guessing, but try ''std::pow (10, - b * z)''.
You have to #include <cmath> first.
Before we go into a debate again on the cmath/std:: vs. math/nostd I have
proposed the latter for two reasons. One: unfortunately I have seen
compilers where include a cxxx header is sure recipe for disater. The other
(way less important) is that it also works in C.
--
WW aka Attila
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