在php的工厂模式 [英] factory pattern in php
问题描述
我想使用工厂模式来创建各种对象。创建哪个对象
取决于传递给工厂的字符串创建
方法。我想避免使用if或switch构造来完成
这个但不确定如何。例如,
....
if($ nextObject ==" login")
{
返回新登录();
}
else if($ nextObject ==" validatedata")
{
返回新验证(aString);
}
....
有什么方法可以避免这种情况吗?
谢谢,迈克
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I want to use a factory pattern to create a variety of objects. Which object
gets created depends on a string that is passed to the factory create
method. I would like to avoid using an if or switch construct to accomplish
this but not sure how. For example,
....
if($nextObject == "login")
{
return new Login();
}
else if($nextObject == "validatedata")
{
return new Validate(aString);
}
....
Is there any way to avoid this?
Thanks, Mike
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推荐答案
nextObject ==" login")
{
返回新登录();
}
else if(
nextObject == "login")
{
return new Login();
}
else if(
nextObject ==" validatedata")
{
返回新的Validate(aString);
}
....
有什么方法可以避免这种情况吗?
谢谢,迈克
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http://www.newsfeeds.com 世界排名第一的新闻组服务! 120,000多个新闻组
---- =东海岸和西海岸服务器农场 - 通过加密实现全隐私= ----
nextObject == "validatedata")
{
return new Validate(aString);
}
....
Is there any way to avoid this?
Thanks, Mike
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"Michael G" <mi****@montana.com> wrote in message
news:42**********@spool9-west.superfeed.net...
我想使用工厂模式创建各种对象。创建哪个对象取决于传递给工厂的字符串
create方法。我想避免使用if或switch构造来实现这一点但不确定如何。例如,
if(
I want to use a factory pattern to create a variety of objects. Which
object gets created depends on a string that is passed to the factory
create method. I would like to avoid using an if or switch construct to
accomplish this but not sure how. For example,
...
if(
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