在php的工厂模式 [英] factory pattern in php

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本文介绍了在php的工厂模式的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想使用工厂模式来创建各种对象。创建哪个对象

取决于传递给工厂的字符串创建

方法。我想避免使用if或switch构造来完成

这个但不确定如何。例如,


....


if($ nextObject ==" login")

{

返回新登录();

}

else if($ nextObject ==" validatedata")

{

返回新验证(aString);

}


....

有什么方法可以避免这种情况吗?


谢谢,迈克


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I want to use a factory pattern to create a variety of objects. Which object
gets created depends on a string that is passed to the factory create
method. I would like to avoid using an if or switch construct to accomplish
this but not sure how. For example,

....

if($nextObject == "login")
{
return new Login();
}
else if($nextObject == "validatedata")
{
return new Validate(aString);
}

....
Is there any way to avoid this?

Thanks, Mike

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推荐答案

nextObject ==" login")

{

返回新登录();

}

else if(
nextObject == "login")
{
return new Login();
}
else if(


nextObject ==" validatedata")

{

返回新的Validate(aString);

}


....

有什么方法可以避免这种情况吗?


谢谢,迈克


---- ==通过Newsfeeds.Com发布 - 无限制 - 未经审查 - 安全使用网新闻== ----
http://www.newsfeeds.com 世界排名第一的新闻组服务! 120,000多个新闻组

---- =东海岸和西海岸服务器农场 - 通过加密实现全隐私= ----
nextObject == "validatedata")
{
return new Validate(aString);
}

....
Is there any way to avoid this?

Thanks, Mike

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news:42 ********** @ spool9-west.superfeed.net ...

"Michael G" <mi****@montana.com> wrote in message
news:42**********@spool9-west.superfeed.net...
我想使用工厂模式创建各种对象。创建哪个对象取决于传递给工厂的字符串
create方法。我想避免使用if或switch构造来实现这一点但不确定如何。例如,



if(
I want to use a factory pattern to create a variety of objects. Which
object gets created depends on a string that is passed to the factory
create method. I would like to avoid using an if or switch construct to
accomplish this but not sure how. For example,

...

if(


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